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Delvig [45]
3 years ago
7

Please hurry

Physics
1 answer:
viktelen [127]3 years ago
6 0

Answer:

The velocity will be "76.8 m/s".

Explanation:

The given values are:

Acceleration,

a = 2.4 m/s²

Time,

t = 32 seconds

By equation of motion,

⇒  v=u+at

On substituting the values, we get

⇒     =0+2.4\times 32

⇒     =0+76.8

⇒     =76.8 \ m/s

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Which pair of quantities represent scalar quantities, and how are they different from vector quantities?
Ann [662]

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2 years ago
A copper rod has a length of 1.3 m and a cross-sectional area of 3.6 10-4 m2. One end of the rod is in contact with boiling wate
sdas [7]

To solve the problem it is necessary to apply the concepts related to heat flow,

The heat flux can be defined as

\frac{dQ}{dt} = H = \frac{kA\Delta T}{d}

Where,

k = Thermal conductivity

A = Area of cross-sectional area

d = Length of the rod

\Delta T= Temperature difference between the ends of the rod

k =388 W/m.\°C Thermal conductivity of copper rod

A = 3.6 *10^{-4} m Area of cross section of rod

\Delta T=100-0=100\°C Temperature difference  

d=1.3m length of rod

Replacing then,

H = \frac{kA\Delta T}{d}

H = \frac{(388)(3.6 *10^{-4})(100)}{1.3}

H=10.7446J

From the definition of heat flow we know that this is also equivalent

H = \dot{m}*L

Where,

\dot{m} = Mass per second

L = 334J/g Latent heat of fusion of ice

Re-arrange to find \dot{m},

H = \dot{m}*L

\dot{m}=\frac{L}{H}

\dot{m}=\frac{334}{10.7446}

\dot{m} = 31.08g/s

\dot{m}= 0.032g/s

Therefore the mass of ice per second that melts is 0.032g

7 0
3 years ago
The speeds of 22 particles are as follows: two at 5.30 cm/s, four at 1.40 cm/s, six at 7.14 cm/s, eight at 1.52 cm/s, two at 7.6
Leona [35]

Answer:

Average velocity is 3.93 cm/s

Root mean square velocity is 4.79 cm/s

Velocity peak to peak is 6.28 cm/s

Explanation:

Speed of 2 particles = 5.3 cm/s

Speed of 4 particles = 1.4 cm/s

Speed of 6 particles = 7.14 cm/s

Speed of 8 particles = 1.52 cm/s

Speed of 2 particles = 7.68 cm/s

v_{avg}=\frac{2\times 5.3+4\times 1.4+6\times 7.14+8\times 1.52+2\times 7.68}{22}\\\Rightarrow v_{avg}=\frac{86.56}{22}\\\Rightarrow v_{avg}=3.93\ cm/s

Average velocity is 3.93 cm/s

v_{rms}=\sqrt{\frac{2\times 5.3^2+4\times 1.4^2+6\times 7.14^2+8\times 1.52^2+2\times 7.68^2}{22}}\\\Rightarrow v_{rms}=\sqrt{\frac{507.34}{22}}\\\Rightarrow v_{rms}=4.79\ cm/s

Root mean square velocity is 4.79 cm/s

v_p=7.68-1.4=6.28\ cm/s

Velocity peak to peak is 6.28 cm/s

8 0
3 years ago
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