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Andru [333]
4 years ago
12

A supersonic jet is 3,600 kilometers east of U.S. airspace and has been flying for 3 hours. If the jet flies at a constant veloc

ity of 2,400 kilometers per hour to the west, how much time will it take the jet to reach U.S. Airspace? Write your answer to the tenths place.
Physics
1 answer:
Marizza181 [45]4 years ago
4 0
It will take 1.34 houra
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"find the ratio of the gravitational force between two planets if the masses of both planets are tripled but the distance betwee
nevsk [136]
Using F=Gmm/r²
the ratio of their forces remains constant
8 0
4 years ago
Polaczono szeregowo cewke ul=120 rezystor ur=100 i kondensator uc=50 Napiecie miezone voltomierzem nie moze byc: u>100 u<1
romanna [79]

Answer:

<u>Translated from Polish language:</u>

  • Coil connected in series ul = 120 resistor ur = 100 and capacitor uc = 50 Voltage with voltmeter must not be:
  • The voltmeter must not be connected in series rather it should be connected in parallel to the circuit to provide much effective results for analyzing the circuits potential difference.

                                                                                                                                                                                 

3 0
3 years ago
The fusion of deuterium and hydrogen is shown in the equation. fill in the missing number.
stellarik [79]

Answer:

= 2

Explanation:

During nuclear fusion, two lighter nuclei of elements combine to form heavy nucleus and also energy is released;

During the process of hydrogen fusion a nucleus of deuterium is formed from two protons with emission of a neutrino.

In this case deuterium fuses with hydrogen nuclei to form helium-3 and also release energy.

That is;

2/1 H + 1/1 H = 3/1 He + energy

8 0
3 years ago
Read 2 more answers
Scientists want to place a 3400.0 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2480.0
BaLLatris [955]

Answer:

Part a)

r = 6.96 \times 10^6 m

Part b)

F_g = 3.004 \times 10^3 N

Part c)

a = 0.88 m/s^2

Part d)

v = \frac{2480}{2} = 1240 m/s

Explanation:

Part a)

As we know that the orbital speed of the satellite is given as

v = 2480 m/s

now we will have

v = \sqrt{\frac{GM_{mars}}{r}}

now we have

M_{mars} = 6.4191 \times 10^{23} kg

R_{mars} = 3.397 \times 10^6 m

now we have

2480 = \sqrt{\frac{(6.67 \times 10^{-11})(6.4191 \times 10^{23})}{r}}

r = 6.96 \times 10^6 m

Part b)

Here force between mars and satellite is the gravitational attraction force which is given as

F_g = \frac{GM_{mars} m}{r^2}

F_g = \frac{(6.67\times 10^{-11})(6.4191 \times 10^{23})(3400)}{(6.96\times 10^6)^2}

F_g = 3.004 \times 10^3 N

Part c)

Acceleration of satellite is the ratio of gravitational force and mass of the satellite

a = \frac{F_g}{m}

a = \frac{3004}{3400}

a = 0.88 m/s^2

Part d)

As we know by III law of kepler

\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}

here we know that T2 = 8 T1

(\frac{1}{8})^2= \frac{r_1^3}{r_2^3}

\frac{r_1}{r_2} = (\frac{1}{2})^2

so we have

r_2 = 4r_1

as we know that speed is given as

v = \sqrt{\frac{GM}{r}}

so we can say since radius is orbit becomes 4 times so the orbital speed must be half

v = \frac{2480}{2} = 1240 m/s

7 0
4 years ago
If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th
Karolina [17]
The path difference between two waves is the distance between the two waves. This distance may be obtained as the product of the order of the maxiuma or minima and the wavelength of the wave. The formula is:
d*sin∅ = nλ

Substituting the values for the distance between slits and the angle:
nλ = 0.05 * sin(0.25)
nλ = 2.18 x 10⁻⁴ m

The path difference is 0.2 millimeters.
7 0
3 years ago
Read 2 more answers
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