Answer:
Ф_cube /Ф_sphere = 3 /π
Explanation:
The electrical flow is
Ф = E A
where E is the electric field and A is the surface area
Let's shut down the electric field with Gauss's law
Фi = ∫ E .dA =
/ ε₀
the Gaussian surface is a sphere so its area is
A = 4 π r²
the charge inside is
q_{int} = Q
we substitute
E 4π r² = Q /ε₀
E = 1 / 4πε₀ Q / r²
To calculate the flow on the two surfaces
* Sphere
Ф = E A
Ф = 1 / 4πε₀ Q / r² (4π r²)
Ф_sphere = Q /ε₀
* Cube
Let's find the side value of the cube inscribed inside the sphere.
In this case the radius of the sphere is half the diagonal of the cube
r = d / 2
We look for the diagonal with the Pythagorean theorem
d² = L² + L² = 2 L²
d = √2 L
we substitute
r = √2 / 2 L
r = L / √2
L = √2 r
now we can calculate the area of the cube that has 6 faces
A = 6 L²
A = 6 (√2 r)²
A = 12 r²
the flow is
Ф = E A
Ф = 1 / 4πε₀ Q/r² (12r²)
Ф_cubo = 3 /πε₀ Q
the relationship of these two flows is
Ф_cube /Ф_sphere = 3 /π
Answer:
(a) Negative Q
(b) Positive Q
Explanation:
Charge is the inherent property of matter due to the transference of electrons.
There are three methods of charging a body.
(i) Charging by friction: When two uncharged bodies rubbed together, then one body gets positive charged and the other is negatively charges it is due to the transference of electrons form one body to another.
(ii) Conduction: when a charged body comes in contact with the another uncharged body, the uncharged body gets the same charge and the charge is distributed equally.
(iii) Induction: When a uncharged body keep near the charged body, the uncharged body gets the same amount of charge but opposite in sign.
(a) When a small tack of charge Q is lowered into the hole, then due to the process of induction, the charge on the inner surface of the shell is - Q.
(b) Due to the process of conduction, the charge on the outer surface of the shell is Q.
Kepler's hypothesis to describe the motions of the planets was derived from
the meticulous observations performed and recorded by Tycho Brahe.
Answer:
Initial position of a body is the position of the body before accelerating or increasing its velocity the position changes and then that position is the final position.
hope it is helpful...
Answer: a) 152 cm
b) 0.725 ms
c) 10°
Explanation:
Given
Frequency of the wave, f = 524 Hz
Speed of the wave, v = 345 m/s
Wavelength of the wave, λ = ?
The relation for wavelength is given by
λ = f/v, on substituting
λ = 524 / 345
λ = 1.52 m or 152 cm
T = 1/v
T = 0.0029 s
T = 2.9 ms.
Note that the phase change is 90°, thus the time required to change the phase by 90° is
t = 2.9 * (90 / 360)
t = 2.9 * 0.25
t = 0.725 ms
The phase difference at a particular instance 4.4 cm apart is
= (4.4 / 152) * 360
= 0.02895 * 360
= 10.422°
a) 152 cm
b) 0.725 ms
c) 10°