Answer:
Correct option is B. It shows the ratio of elements in the compound.
Explanation:
Empirical formula is the simplest form of the chemical formula. It shows the simplest ratio of atoms in compounds. It is determined by %age of each element.
Answer:
Salt is a solid
Explanation: Compounds with this kind of electrostatic attraction, called ionic bonds, are almost always solid at room temperature. But table salt can melt into liquid. onsisting of sodium atoms with positive charges and chloride atoms with negative charges
Answer:
Separation method for various ingredients are
1. Paneer from curdled milk. - Filtration
2. Chalk powder from water. - Filtration
3. Sand from salt solution. - Evaporation
4. Saw dust from water. - Skim off, sieve or filter
5. Tea leaves from brew. - Filtration.
Explanation:
By the help of a muslin cloth the paneer is separated from the curdled milk, the process is called as the filtration. The paneer will remain in the cloth and curdled milk will be removed. Separation of chalk powder from water is very easy by the process of filtration, after the filtration the chalk powder retentate and the filtrate obtained is the water in absence of chalk. Salt and sand water separation can be done with the help of evaporation. Separation of the saw dust from water takes place by the method of sieving or sedimentation. The tea leaves are separated from brew by filtration.
Answer: 1.037M
Explanation:
Since the rate constant unit is per seconds, therefore it is a first order reaction.
First order reaction equation is given as
InA= -kt +InAo
Where,Ao is the initial concentration of reactant =0.600M
A is the concentration of reactant at a specifies time t=3×60=180s
and k is the rate constant
InA = -6.50×10^-3 ×180 +In(0.6)
InA = -1.17 + 0.5108
InA= -1.680
A = e-1.680
A= 1.037M
Therefore the concentration after 3minutes is 1.037M
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions. So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3.
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole. So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
