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Pie
3 years ago
7

A rescue airplane is diving at an angle of 37o below the horizontal with a speed of 250 m/s. It releases a survival package when

it is at an altitude of 600 m. If air resistance is ignored, the horizontal distance of the point of impact from the plane at the moment of the package's release is
Physics
1 answer:
igomit [66]3 years ago
5 0

Answer:

796.2 m.

Explanation:

A sketch of the given question forms a right angled triangle with two given sides and a non included angle. Applying the appropriate trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

Let the horizontal distance required be represented by x, so that;

Tan 37^{o} = \frac{600}{x}

0.7536 = \frac{600}{x}

⇒ x = \frac{600}{0.7536}

      = 796.1783

x = 796.2 m

Thus, the horizontal distance of the point of impact is 796.2 m.

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According to Coulomb's law, the magnitude of the electric force between two point charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

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