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Igoryamba
3 years ago
13

What forces were exerted during the air resistance experiment?

Physics
1 answer:
zepelin [54]3 years ago
6 0

The forces that were exerted during the air resistance was the gravity.

<u>Explanation:</u>

Air resistance is the frictional power air applies against a moving article. As an article moves, air opposition backs it off. The quicker the article's movement, the more prominent the air obstruction applied against it.

The force acting upon the objects dropped in the air was air resistance and gravity. The force acting upon the objects dropped in the vacuum was gravity only.

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A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?
MakcuM [25]

Answer:

It will become a temporary magnet because the domains will easily realign.

Explanation:

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3 years ago
What new characteristics did john dalton add to the model of the atom
kicyunya [14]

Answer:

All atoms of an element are identical. The atoms of different elements vary in size and mass. Compounds are produced through different whole-number combinations of atoms. A chemical reaction results in the rearrangement of atoms in the reactant and product compounds.

HOPE THIS HELPED!!!!!!!!!!!!!!!!!!! XDDDDDDDDDDD

7 0
3 years ago
A student pushes a box with a total mass of 50 kg. What is the net force on the box if it accelerates 1.5 m/s
Harrizon [31]
We now that follow newton rules f=ma so net force equal to mass*acceleration=>f=50*1.5=75 N
3 0
3 years ago
Read 2 more answers
Lauren throws her first pitch of the season for her school's softball team. If the ball travels 80 feet and takes 1.58 seconds t
kow [346]

Answer:

<em><u>5</u></em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>3</u></em><em><u> </u></em><em><u>f</u></em><em><u>t</u></em><em><u>/</u></em><em><u>s</u></em><em><u> </u></em><em><u>(</u></em><em><u>2</u></em><em><u>d</u></em><em><u>p</u></em><em><u>)</u></em>

Explanation:

Speed = Distance/Time

80/1.58 = 50.63291139

= <u>50.63</u><u> </u><u>f</u><u>t</u><u>/</u><u>s</u> (2dp)

6 0
2 years ago
The temperature of a solution will be estimated by taking n independent readings and averaging them. Each reading is unbiased, w
Viktor [21]

Answer:

68 readings.

Explanation:

We need to take this problem as a statistic problem where the normal distribution table help us.

We can start considerating that X is the temperature of the solution, then

0.9 = P(|\bar{x}-\mu|

0.9 = P(\frac{|\bar{x}-\mu|}{\frac{\sigma}{\sqrt{n}}}

0.9 = P(|Z|

For a confidence level of 90% our Z_{critic} is 1.645

Therefore,

\frac{0.1}{\frac{\sigma}{\sqrt{n}}} = 1.645

Substituting for \sigma = 5 and re-arrange for n, we have that n is equal to

n=(\frac{1.645\sigma}{0.1})^2

n=\frac{(1.645)^2(0.5)^2}{0.1^2}

n=67.65

n=68

We need to make 68 readings for have a probability of 90% and our average is within 0.1\°\frac

3 0
2 years ago
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