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skad [1K]
3 years ago
13

A population of bacteria is growing according

Mathematics
1 answer:
NISA [10]3 years ago
4 0

Answer:

13.4

Step-by-step explanation:

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one rectangular prism has a base area of 120 square inches, and a height of 12 feet. a second has dimensions of 84 inches, 6 fee
dangina [55]
Volume of first prism = 120 x 12 = 1,440 cubic feet
Volume of second prism = 84 x 6 x 16 = 8,064 cubic feet

The volume of the second prism is more than that of the first.
5 0
4 years ago
The Question is above ⤴​
melomori [17]

Answer:

i believe its A

Step-by-step explanation:

4 0
3 years ago
The smaller cone is replaced with another cone of equal radii, but a height twice as big.
Bess [88]
Let's make this simple. Let's have the small cone have a radius 1 and the height 1. This would make the bigger cone have a radius of 1 and the height of 2.

With this information, lets get the volume of both cones. The formula is this:

V =  \dfrac{(\pi r^2 h)}{3}

Plug in numbers:
Small cone: V =  \dfrac{(\pi 1^2 \times 1)}{3}
Big cone: V =  \dfrac{(\pi 1^2 \times 2)}{3}

The small cone has a volume of \dfrac{\pi}{3}
The big cone has a volume of \dfrac{2 \pi}{3}

Now, you want to find how many small cones you need to have the same total volume of the big cone.

\dfrac{2\pi}{3} -  \dfrac{\pi}{3} =  \dfrac{\pi}{3} 


You have the difference of pi over 3 comparing the big cone to the small one. You realize that the small cone has the same volume of that. Therefore, you need 2 small cones to have the same total volume as the larger cone
6 0
3 years ago
Find the decimal that is equivalent to:
NemiM [27]

Answer:

0.5833333

Step-by-step explanation:

5 0
3 years ago
Give an example of a function with both a removable and a non-removable discontinuity.
navik [9.2K]

Answer:

(x+5)(x-3) / (x+5)(x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator.  It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x.  In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

8 0
3 years ago
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