What is the force needed to throw a ball 7 meters when 1778 J of work is done?

A 500kg car is driving through a neighborhood at 20m/s. Then the car hits a speed bump which causes it to slow to 15m/s. What wa

lawyer [7]

Based on the formula for calculating impulse, the impulse of the speed bump to the car is 2500 Ns.

<h3>What is the impulse of the speed bump?</h3>

Impulse = change in momentum

momentum = mass * velocity

Change in momentum = mu - mv

where u is initial velocity

v is final velocity

Impulse = 500 * 20 - 500 * 15

Impulse = 2500 Ns

Therefore, the impulse of the speed bump to the car is 2500 Ns.

Learn more about impulse at: brainly.com/question/297527

5 0

3 years ago

Dinitrogen oxide has?

Vesnalui [34]

Two atoms of the element bind to form dinitrogen and it’s a colourless and odorless diatomic gas with the formula N2. Also Dinitrogen forms up about 78% of earths atmosphere

3 0

3 years ago

If the wavelength of a 4.65 ✕ 102 Hz sound in freshwater is 3.45 m, what is the speed of sound in fresh water?

natima [27]

Answer:

Explanation:

Given that, the wavelength is 3.45m

λ=3.45m

Frequency is 4.65×10^2Hz

F=4.65×10^2Hz

Speed is given as

V=Fλ

Then,

V=4.65×10^2× 3.45

V=1604.25m/s

The speed of sound in fresh water is 1604.25m/s

8 0

3 years ago

Read 2 more answers

A tennis ball is thrown vertically upward with an initial velocity of +6.2 m/s. What will the ball’s velocity be when it returns

anastassius [24]

Answer:

$v_{f}=-6.2 m/s$

Explanation:

The ball will rise decreasing its speed until it reaches the highest point where its speed will be zero. From this point the tennis ball will begin to fall again, in the free fall the tennis ball will gain speed but now in the opposite direction. When it returns to the same point where it was launched, its speed will be the same as the one that was launched but with the opposite sign.

$v_{f}=-6.2 m/s$

We can check this using the equation:

$v_{f}^2=v_{i}^2+2gh$

where $v_{i}=+6.2 m/s$

ang h is the height, but because the ball returns to the same point where it started, h =0

then

$v_{f}^2=v_{i}^2$

$v_{f}=v_{i}$

the initial and final velocity will be the same in number, but we know that the ball is going in the opposite direction, so the final velocity must have the opposite sign from the initial velocity

so if $v_{i}=+6.2 m/s$ ,

$v_{f}=-6.2 m/s$

4 0

3 years ago

A spring stretches 0.018 m when a 2.8-kg object is suspendedfrom its end. How much mass should be attached to this spring sothat

agasfer [191]

Answer:

m = 4.29 kg

Explanation:

Given that,

Mass of the object, m = 2.8 kg

Stretching in the spring, x = 0.018 m

Frequency of vibration, f = 3 Hz

Let m is the mass of the object that is attached to the spring. When it is attached the gravitational force is balanced by the force on spring. It is given by :

$mg=kx$