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3 years ago

12

Order from least to greatest 7.081 , 7.81 , 7.002 , 7.14

2 answers:

Ludmilka [50]3 years ago

8 0

7.14,7.81,7.002,7.081

Soloha48 [4]3 years ago

7 0

7.002, 7.081, 7.81, 7.14

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Subtract -4a^2-2ab+9b^2 from 7a^2-3ab+5b^2

tresset_1 [31]

${7a}^{2} - 3ab + {5b}^{2} - ( - {4a}^{2} - 2ab + {9b}^{2}) \\ = {7a}^{2} - 3ab + {5b}^{2} + {4a}^{2} + 2ab + - {9b}^{2}) \\ = {7a}^{2} + {4a}^{2} - 3ab + 2ab + {5b}^{2} - {9b}^{2}) \\ = {11a}^{2} - ab - {4b}^{2}$

<u>Answer</u><u>:</u>

<u> ${11a}^{2} - ab - {4b}^{2}$ </u>

Hope you could understand.

If you have any query, feel free to ask

7 0

3 years ago

Use f(x) = 2 x and f-'(x) = 2x to solve the problems.

Marrrta [24]

Answer:

a) 1

b) 2

c) 2

Step-by-step explanation:

a) $f(2)$ means find the output for $\frac{1}{2}x$ when $x=2$ .

$\frac{1}{2}(2)$

$\frac{2}{2}$

$1$

b) $f^{-1}(1)$ means find the output for $2x$ when $x=1$

$2(1)$

$2$

c) If $f$ and $f^{-1}$ are truly inverses then $f(f^{-1}(u))=u$ and $f^{-1}(f(u))=u$ as long as $u$ satisfies the domains.

So we should be able to conclude that $f^{-1}(f(2))=2$ with no work.

However, I will also show work.

$f^{-1}(f(2))$

$f^{-1}(1)$ since $f(2)=1$ from part a.

$2$ since $f^{-1}(1)=2$ from part b.

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3 years ago

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Answer:

The correct answer would be D I believe.

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Step-by-step explanation:

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kramer

The answer to this question is Wyatt could walk 27 miles in 9 hours.

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3 years ago

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You're shopping for a new 45" HD TV.

Bezzdna [24]

Answer:

Best Buy 30% of 379.99=113.99

379.99-113.99=$266.00

Costco 15% 409.99=61.50

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399.99-99.99=300

Best Buy has the best offer.

Step-by-step explanation:

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3 years ago