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Monica [59]
3 years ago
12

Order from least to greatest 7.081 , 7.81 , 7.002 , 7.14

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0
7.14,7.81,7.002,7.081
Soloha48 [4]3 years ago
7 0
7.002, 7.081, 7.81, 7.14
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A quadratic function is shown. f(x) = -x^2+7x-12 one factor of this function is (x-4). What is the other factor of the quadratic
Alexus [3.1K]

Answer:

The other term is<u> (x-3)</u>

Step-by-step explanation:

The quadratic function is:

f(x)=-x^{2}+7x-12

Factoring this function we will have:

f(x)=-(x-4)(x-3)

Therefore, the other term is<u> (x-3).</u>

I hope it helps you!

3 0
2 years ago
Mark uses an app that shows him how many kilometers he has run to prepare for a marathon. The app said he ran 9.654 kilometers.
Viefleur [7K]

Answer:

5.9987174899

Step-by-step explanation:

9.654km / 1.609344

= 5.9987174899mi

4 0
2 years ago
3) Round answer to the nearest hundredth. *
DochEvi [55]

Answer:

80 mm

Step-by-step explanation:

Pythagorean theorm can be applied here to solve for the length of the last leg, a^{2} + b^{2} = c^{2}, where (a) and (b) are the legs of the triangle and (c) is the hypotenuse. We can rearrange the pythagorean theorm for our purposes like the following:

b = √c^2 - √a^2

  = √(82)^2 - √(18)^2

  = √6724 - √324

  = √6400

  = 80 mm

5 0
2 years ago
The absolute value function, f(x) = –|x| – 3, is shown. What is the range of the function? all real numbers all real numbers les
Harman [31]

Answer:

  all real numbers less than or equal to –3

Step-by-step explanation:

Look at the y-values that the graph shows. There are none greater than -3. Any value of -3 or less is possible.

5 0
3 years ago
Read 2 more answers
If f(p) divided by x-p and x-q have the same remainder
oee [108]
Hello,


x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)

Let's use Horner's division

.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3

The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3


Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0

And here, Mehek are there sufficients explanations?
3 0
2 years ago
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