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sergey [27]
3 years ago
6

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Physics
2 answers:
alex41 [277]3 years ago
8 0

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Hehdbeeufhrbfuibcdsjibvhisbcznchbvrjkvn? Kiffbcrrhhsdfvcbiajsbnfucjoansdzuijcndj!!!

Andrei [34K]3 years ago
5 0

Jnkmj jnmmjnkmjnkmjmsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssc mmmmmmmmmmmmmmmmmmmm

Jnkmj jnmmjnkmjnkmjmsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssc mmmmmmmmmmmmmmmmmmmm

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To hit the target the crew drop the crate before the plane is directly over the target. It is because <span>because the cargo has forward velocity and therefore before it reaches the ground it travels some distance. The answer is A. Hope it helps. </span>
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What makes a substance, such as<br> aluminum, a good conductor?
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For a material to be a good conductor, the electricity passed through it must be able to move the electrons; the more free electrons in a metal, the greater its conductivity.

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Consider the Uniform Circular Motion Gizmo configured as shown. Notice that, under the current settings, |a|=0.50m/s2. What chan
Eddi Din [679]

To increase the centripetal acceleration to 2.00 m/s^2, you can double the speed or decrease the radius by 1/4

Explanation:

An object is said to be in uniform circular motion when it is moving at a constant speed in a circular path.

The acceleration of an object in uniform circular motion is called centripetal acceleration, and it is given by

a=\frac{v^2}{r}

where

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r is the radius of the circular path

In the problem, the original centripetal acceleration is

a=0.50 m/s^2

We want to increase it by a factor of 4, i.e. to

a'=2.00 m/s^2

We notice that the centripetal acceleration is proportional to the square of the speed and inversely proportional to the radius, so we can do as follows:

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v' = 2v

This way, the new acceleration is

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so, 4 times the original acceleration

- We can decrease the radius to 1/4 of its original value:

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So the new acceleration is

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Learn more about centripetal acceleration:

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3 years ago
A well-thrown ball is caught in a well-padded mitt. If the deceleration of the ball is 2.10×104 m/s2 , and 1.85 ms (1 ms = 10−3
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Answer:

u = - 38.85 m/s^-1

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given data:

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v = u +at

0 =  u + 2.10*10^4 *1.85*10^{-3}

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u = - 38.85 m/s^-1

negative sign indicate that the ball bounce in opposite directon

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