Answer:
no it will not glow hope help you stay happy
A ground wire provides a conducting path to the earth which is separate and independent from the path of an electrical appliance. Also, a ground wire is an additional pathway for an electric current to safely return to the ground without imposing danger to anyone in the event that a short circuit might occur. This is particularly important for shock hazard since it forces the breaker to trip by supplying a path to the ground if ever a hot wire comes in contact with a metal case of the appliance.
A fuses and circuit breakers limit the current which can possibly flow in a circuit. The metal filament present in the fuse will melt and break the connection. On the other hand, the circuit breaker with its bimetallic strip's heating effect causes a bending and tripping of a spring-loaded switch.
<h2>
Answer: 450 Bq</h2>
Explanation:
This problem can be solved using the Radioactive Half Life Formula:
(1)
Where:
is the final amount of radioisotope (decay rate)
is the initial amount of the radioisotope
is the time elapsed
is the half life of the radioisotope
Knowing this, let's find
from (1):
(2)
(3)
Finally:
>>> This is the decay rate of the radioisotope
Note it is in Becquerels (Bq), which is the derived unit approved by the <u>International System of Units</u> for radioactivity
Answer:
The voltage will be 0.0125V
Explanation:
See the picture attached
Answer:
The speed of the stone is 0.6138 c.
(B) is correct option.
Explanation:
Given that,
Mass of stone m= 0.6
Relativistic mass = 0.76
We need to calculate the speed
Using formula of rest mass
![m_{r}=\dfrac{m_{0}}{\sqrt{1-\dfrac{v^2}{c^2}}}](https://tex.z-dn.net/?f=m_%7Br%7D%3D%5Cdfrac%7Bm_%7B0%7D%7D%7B%5Csqrt%7B1-%5Cdfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D%7D)
![v^2=(\dfrac{m_{0}^2}{m_{r}^2}-1)c^2](https://tex.z-dn.net/?f=v%5E2%3D%28%5Cdfrac%7Bm_%7B0%7D%5E2%7D%7Bm_%7Br%7D%5E2%7D-1%29c%5E2)
Put the value into the formula
![v^2=(\dfrac{0.6^2}{0.76^2}-1)\times c^2](https://tex.z-dn.net/?f=v%5E2%3D%28%5Cdfrac%7B0.6%5E2%7D%7B0.76%5E2%7D-1%29%5Ctimes%20c%5E2)
![v=\sqrt{0.37673c^2}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B0.37673c%5E2%7D)
![v=0.6138c](https://tex.z-dn.net/?f=v%3D0.6138c)
Hence, The speed of the stone is 0.6138 c.