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timama [110]
3 years ago
12

The crew of a cargo plane wishes to drop a crate of supplies on a target below. To hit the target, when should the crew drop the

crate? Ignore air resistance.
a) Before the plane is directly over the target
b) When the plane is directly over the target
c) After the plane has flown over the target
Physics
2 answers:
lara [203]3 years ago
5 0
To hit the target the crew drop the crate before the plane is directly over the target. It is because <span>because the cargo has forward velocity and therefore before it reaches the ground it travels some distance. The answer is A. Hope it helps. </span>
sergiy2304 [10]3 years ago
5 0

Answer:

a) Before the plane is directly over the target  

Explanation:

When a crate would be dropped from the cargo plane, its initial vertical velocity would be zero (free fall) but it would still have horizontal velocity of the moving plane. Therefore, the falling crate would transverse a parabolic path.

In order to make it hit the target, the crate should be dropped before the plane is directly over the target because of the horizontal component of net velocity will take the crate towards the target.

Thus, option a is correct.

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Why are some substances dissolve both polar and nonpolar substances?
dlinn [17]

Answer:

Because water is polar and oil is nonpolar, their molecules are not attracted to each other.<em> polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.</em>

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<em>please mark me as the brainliest :) </em>

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<em>use your brain :)</em>

8 0
3 years ago
If a truck has the mass of 2,000 kilometres and a velocity of 35 m/s, what is the momentum
alexira [117]

Answer:

<h2>70,000 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 2000 × 35

We have the final answer as

<h3>70,000 kg.m/s</h3>

Hope this helps you

5 0
3 years ago
I need help with these four problems.. anyone??
babunello [35]
1) 14g
2) 24 fl oz
3)10 cups
4)12 and 1/2 cups
8 0
3 years ago
a car traveling at a speed of 72km/h is uniformly returded and comes to rest after 8 seconds if the car with the occupants has a
cricket20 [7]

Answer:

the breaking force is 12

Explanation:

7 0
3 years ago
An unbanked (flat) curve of radius 150 m is rated for a maximum speed of 32.5 m/s. At what maximum speed, in m/s, should a flat
Rasek [7]

Answer:

The maximum speed is 21.39 m/s.

Explanation:

Given;

radius of the flat curve, r₁ = 150 m

maximum speed, v_{max} = 32.5 m/s

The maximum acceleration on the unbanked curve is calculated as;

a_c_{max} = \frac{V_{max}^2}{r} \\\\a_c_{max} = \frac{32.5^2}{150} \\\\a_c_{max} = 7.04 \ m/s^2

the radius of the second flat curve, r₂ = 65.0 m

the maximum speed this unbanked curve should be rated is calculated as;

a_c_{max} = \frac{V_{max}^2}{r_2} \\\\V_{max}^2 = a_c_{max}  \ \times \ r_2\\\\V_{max} = \sqrt{a_c_{max}  \ \times \ r_2} \\\\V_{max} =\sqrt{7.04 \ \times \ 65} \\\\V_{max} = 21.39 \ m/s

Therefore, the maximum speed is 21.39 m/s.

3 0
3 years ago
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