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timama [110]
3 years ago
12

The crew of a cargo plane wishes to drop a crate of supplies on a target below. To hit the target, when should the crew drop the

crate? Ignore air resistance.
a) Before the plane is directly over the target
b) When the plane is directly over the target
c) After the plane has flown over the target
Physics
2 answers:
lara [203]3 years ago
5 0
To hit the target the crew drop the crate before the plane is directly over the target. It is because <span>because the cargo has forward velocity and therefore before it reaches the ground it travels some distance. The answer is A. Hope it helps. </span>
sergiy2304 [10]3 years ago
5 0

Answer:

a) Before the plane is directly over the target  

Explanation:

When a crate would be dropped from the cargo plane, its initial vertical velocity would be zero (free fall) but it would still have horizontal velocity of the moving plane. Therefore, the falling crate would transverse a parabolic path.

In order to make it hit the target, the crate should be dropped before the plane is directly over the target because of the horizontal component of net velocity will take the crate towards the target.

Thus, option a is correct.

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the atomic mass is 11 because the mass is the sum of protons and neutrons
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Who ever gets it right I will give Brainly and 20 points.
svetlana [45]

Answer:

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Explanation:

3 0
2 years ago
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Two workers are sliding 290 kg crate across the floor. One worker pushes forward on the crate with a force of 430 N while the ot
m_a_m_a [10]

Answer:0.27

Explanation:

Given

One worker Pushes with force F_1=430 N

other Pulls it with a rope of rope F_2=360 N

mass of crate m=290 kg

both forces are horizontal and crate slides with a constant speed

Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it

f_r=F_1+F_2

where f_r is the friction force

f_r=430+360

f_r=790 N

f_r=\mu N

where \muis the coefficient of static friction

N=mg

790=\mu 29\cdot 9.8

\mu =0.27

6 0
3 years ago
In magazine car tests an important indicator of performance is the zero to 60 mph (0 to 96.6 km/h) acceleration time. A time bel
slavikrds [6]

Answer:

2.73414 seconds

467622.66798 J

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

v=60\times \dfrac{1609.34}{3600}=26.822\ m/s

mgh=\dfrac{1}{2}mv^2\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{26.822^2}{2\times 9.81}\\\Rightarrow h=36.66766\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow 36.66766=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{36.66766\times 2}{9.81}}\\\Rightarrow t=2.73414\ s

or

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{26.822-0}{9.81}\\\Rightarrow t=2.73414\ s

The time taken is 2.73414 seconds

The potential energy is given by

U=mgh\\\Rightarrow U=1300\times 9.81\times 36.66766\\\Rightarrow U=467622.66798\ J

The change in potential energy is 467622.66798 J

5 0
3 years ago
Hannah just finished building a house of cards that stands four stories high. She is worried that it will fall down. Which of th
Tju [1.3M]
A.) <span>If no unbalanced force acts upon the house of cards, then it will remain standing forever.

[ Other Statements doesn't make any sense in Physics, they can be true in some situation & can't be false, option A is the only answer ]
Hope this helps!</span>
6 0
3 years ago
Read 2 more answers
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