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Novosadov [1.4K]
3 years ago
8

A car weighing 12,000 N is parked on a 36° slope. The car starts to roll down the hill. What is the acceleration of the car?​

Physics
1 answer:
Delicious77 [7]3 years ago
4 0

Answer: 5.8 m/s squared

Explanation: just got that question lol

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Which statement correctly differentiates between transmitters and receivers?
jeka94

Answer:

Transmitters send radio waves, and receivers capture radio waves.

Explanation:

Let us look at each of the choices one by one:

(1).Transmitters have antennas, and receivers do not have antennas.

Nope. To send signals transmitters need antennas, and to receive signals   the receivers need antennas as well.

(2). Transmitters send radio waves, and receivers capture radio waves.

This is true. Transmitters are for transmitting and receivers are for     receiving EM signals.

(3). Transmitters have demodulators, and receivers have modulators.

No, it is the other way around. Transmitters have modulators, and          receivers have demodulators.

(4). Transmitters do not have amplifiers, and receivers have amplifiers.

Nope. Both the transmitters and the receivers need amplifiers.    Transmitters need them to increase the power of the broadcast, and   receivers need them to amplify the signal for processing.

Therefore, only the 2nd statement "Transmitters send radio waves, and receivers capture radio waves." is correct.

7 0
3 years ago
Read 2 more answers
Can a body have zero velocity and finite acceleration?Explain​
sergejj [24]

Answer:

Kinda? Depends what the question is fully asking

Explanation:

Acceleration is a change in velocity. So I guess if the velocity of something is -2 m/s and its positively accelerating at a value of +1 m/s, then that means every second its velocity changes by +1m/s.

So that -2 m/s thing after one second will be going -1 m/s.

After another second it'll be going 0 m/s.

After another itll be going +1 m/s and so on.

So at one point for a brief moment, it can have an acceleration but be at 0 m/s velocity.

5 0
3 years ago
The earth has a vertical electric field at the surface, pointing down, that averages 119 N/C . This field is maintained by vario
velikii [3]

Answer:

q=5.37*10^{5}C

Explanation:

If we assume that the Earth is a spherical conductor, according to  Gauss's Law, the electric field is given by:

E=\frac{kq}{r^2}

Here k is the Coulomb constant, the excess charge on the Earth's surface and r its radius. Solving for q:

q=\frac{Er^2}{k}\\q=\frac{119\frac{N}{C}(6.371*10^6m)^2}{8.99\frac{N\cdot m^2}{C^2}}\\q=5.37*10^{5}C

5 0
4 years ago
PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works
steposvetlana [31]

Solved your another question same like this with scaling to Cm this time we go with metre(m)

Scale factor

  • 1km=10³m
  • 1m=10^{-3}km

Mercury

  • 58000m

Ven us

  • 108000m

Earth

  • 150000m

Mars

  • 228000m

Jupiter

  • 778000m

Saturn

  • 1430000m

Uranus

  • 2870000m

Neptune

  • 4500000m

7 0
2 years ago
A motor-driven winch pulls a 50.0 kg student 5.00 m up the rope at a constant speed of 1.25 m/s. how much power does the motor u
nadya68 [22]
Power is the rate work done given by dividing work done by unit time. It is measured in watts equivalent to J/s.
In this case the force by the student is mg = 490 N (taking g as 9.8m/s²)
Work done is given by force × distance,
Therefore, Power =(force × distance)/ time, but velocity/speed =distance/time
Thus, Power = force × speed/velocity
                     = 490 N × 1.25
                     = 612.5 J/S (Watts)
Hence, power will be 612.5 Watts.
7 0
4 years ago
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