A car weighing 12,000 N is parked on a 36° slope. The car starts to roll down the hill. What is the acceleration of the car?
1 answer:
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1) Impulse: -32,000 kg m/s
The impulse acting on the car is equal to the change in momentum of the car:
where in this problem we have
m = 1000 kg is the mass of the car
v = 0 m/s is the final velocity of the car
u = 32 m/s is the initial velocity of the car
Substituting values into the equation, we find
2) -4751 N
The impulse exerted on the car is also equal to the product between the average force, F, and the duration of the collision, t:
where in this situation we know
is the impulse
t = 7 s is the duration of the collision
Solving the formula for F, we find the average force:
and the negative sign means that the force is in the opposite direction to the motion of the car.
Answer:
Explanation:
We could use the following suvat equation:
where
s is the vertical displacement of the coin
v is its final velocity, when it hits the water
t is the time
g is the acceleration of gravity
Taking upward as positive direction, in this problem we have:
s = -1.2 m
And the coin reaches the water when
t = 1.3 s
Substituting these data, we can find v:
where the negative sign means the direction is downward.