How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms?

Chemistry

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =

83 g CaCO3

So answer D), although three significant digits are not justified.

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Answer:

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2 years ago

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Answer:

Explanation:

The movement of the electrons is illustrated in the picture attached to this answer. It is a four-step reaction mechanism.

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Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.

Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.

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