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2 years ago

How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms?

Chemistry

1 answer:

Tamiku [17]2 years ago

7 0

Answer:

(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =

83 g CaCO3

So answer D), although three significant digits are not justified.

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How might a fact be disproved? Are there some facts that will never be disproved

Paha777 [63]

A fact can be disapproved with further evidence different details. So basically evidence can change a fact!! Hope this helps

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2 years ago

A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is

Vlada [557]

Answer:

$c=0.127\ J/g^{\circ} C$

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

$Q=mc\Delta T$

c is specific heat of the metal

$c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C$

So, the specific heat of metal is $0.127\ J/g^{\circ} C$ .

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2 years ago

One of the postulates of bohr's atomic model of a moving electron is that angular momentum of a moving electron is quantized. Ex

oksano4ka [1.4K]

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1 year ago

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1 year ago

Which electrolyte is used in an alkali fuel cell?

zaharov [31]

i think..
potassium hydroxide..

4 0

2 years ago

Read 2 more answers