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xeze [42]
3 years ago
7

How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms?

Chemistry
1 answer:
Tamiku [17]3 years ago
7 0

Answer:

(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =  

83 g CaCO3

So answer D), although three significant digits are not justified.

Your welcome! Please give me brainiest and have a Great day! <3

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