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stiks02 [169]
3 years ago
5

When Iodine-131 emits a β particle (beta particle), what nuclide is produced? *

Chemistry
2 answers:
k0ka [10]3 years ago
5 0

When Iodine-131 emits a β particle will produce Xe-131

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

So for reaction Iodine-131 :

\tt _{53}^{131}I\rightarrow _{-1}^0\beta +_{54}^{131}Xe

erastovalidia [21]3 years ago
5 0

Question, Answer, and Explanation are within the picture of files:

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Their atomic number
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3 years ago
If you had a mixture of ethanol, glycerol, ethylene glycol, methanol, and water, how could you separate these five substances ou
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Fractional distillation

Explanation:

The best way to separate the mixtures out is through the process of fractional distillation.

In fractional distillation, liquid - liquid mixtures are separated based on the differences in boiling point of their components. Let us examine the boiling points of the component of the mixtures:  

     Ethanol                  78⁰C

     Glycerol                290⁰C

     Ethylene glycol     197.6⁰C

     Methanol               64.7⁰C

     Water                     100⁰C

We see that the liquids in the mixture have different boiling points. In this process, the mixture is heated in a distillation column. When the boiling point of any component is reached, it will rise up in the column and can be channeled to a condenser where it is cooled and collected.

The liquid with the least boiling point is first separated with the one with the highest boiling is recovered last:

   Order of recovery;

               Methanol               64.7⁰C

               Ethanol                  78⁰C

                Water                    100⁰C

               Ethylene glycol     197.6⁰C

                Glycerol                290⁰C

Learn more:

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3 0
3 years ago
The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

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3 years ago
Hydrofluoric acid (HF) can be prepared according to the following equation:
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Given the balanced equation:

( Reaction type : double replacement)

CaF2 + H2SO4 → CaSO4 + 2HFI

We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.

This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.

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For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.

Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.

3 0
3 years ago
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You are walking in a clear-cut section of forest a few days after a heavy rainstorm. A nearby stream is very muddy and has many
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Answer:

the storm knocked down trees creating a dam blocking the path for water to move

Explanation:

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