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Answer:
See explanation below
Explanation:
In this case, let's see both molecules per separate:
In the case of SeO₂ the central atom would be the Se. The Se has oxidation states of 2+, and 4+. In this molecule it's working with the 4+, while oxygen is working with the 2- state. Now, how do we know that Se is working with that state?, simply, let's do an equation for it. We know that this molecule has a formal charge of 0, so:
Se = x
O = -2
x + (-2)*2 = 0
x - 4 = 0
x = +4.
Therefore, Selenium is working with +4 state, the only way to bond this molecule is with a covalent bond, and in the case of the oxygen will be with double bond. See picture below.
In the case of CO₂ happens something similar. Carbon is working with +4 state, so in order to stabilize the charges, it has to be bonded with double bonds with both oxygens. The picture below shows.
Answer: C) Tetrahedral
Explanation:
The number of electron pairs is 4 that means the hybridization will be
but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.
Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be
.
Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be
.
Trigonal bipyramidal geometry is possible when number of electron pairs is 5 and the hybridization will be
.
Octahedral geometry is possible when number of electron pairs is 6 and the hybridization will be
.