Answer:
1260 is the correct answer
remember multiply them :)
Step-by-step explanation:
Answer:
A. Trinomial
Step-by-step explanation:
It says it's a polynomial and that based on the number of terms. So right then you can cancel out cubic and quadratic because they aren't polynomials. Also:
Cubic is just a variable with the exponent of 3. Examples:

Binomial is a polynomial with 2 terms. Examples:

A quadratic has a division sign.
With convolution theorem the equation is proved.
According to the statement
we have given that the equation and we have to evaluate with the convolution theorem.
Then for this purpose, we know that the
A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.
And the given equation is solved with this given integral.
So, According to this theorem the equation becomes the

Then after solving, it become and with theorem it says that the

Hence by this way the given equation with convolution theorem is proved.
So, With convolution theorem the equation is proved.
Learn more about convolution theorem here
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Answer:
Tn = 6.4 + 1.8n
Step-by-step explanation:
Given
Sequence: 8.2, 10, 11.8, 13.6
Required
The formula of the sequence.
First, the type of the sequence needs to be determined (arithmetic or geometric)
It is an arithmetic sequence because each successive sequence is separated by a common difference..
The common difference is represented by d and it's calculated as follows.
d = 10 - 8.2 or 11.8 - 10 or 13.6 - 11.8
Each of the above gives
d = 1.8
Now, that we have the common difference; the next is to determine the formula using the Arithmetic Progression formula.
Tn = T1 + (n - 1)d
Where T1 is the first term of the progression; T1 = 8.2
By substituting 8.2 for T1 and 1.8 for d.
This gives
Tn = 8.2 + (n - 1) * 1.8
Open bracket
Tn = 8.2 + 1.8 * n - 1 * 1.8
Tn = 8.2 + 1.8n - 1.8
Collect like terms
Tn = 8.2 - 1.8 + 1.8n
Tn = 6.4 + 1.8n
Hence, the formula of the sequence is Tn = 6.4 + 1.8n
A is the answer if I calculated right ;)