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Charra [1.4K]
3 years ago
7

The average daily balance of a credit card for the month of November was $700, and the unpaid balance at the end of the month wa

s $1400. If the monthly interest rate is 1.3% of the average daily balance, what is the total balance on the next billing date December 1? Round your answer to the nearest cent. Do not use commas to separate numbers or dollar signs. For example, $5,678.00 should be entered as 5678.00.
Mathematics
1 answer:
lakkis [162]3 years ago
8 0

9514 1404 393

Answer:

  $1409.10

Step-by-step explanation:

The interest is added to the unpaid balance to obtain the total balance.

  $700×1.3% + 1400 = $9.10 +1400 = $1409.10

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harina [27]

Answer :

  • 4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

{\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}

\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}

\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}

Therefore,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: the  \: wall = length \times breadth \times height}}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: the  \: wall = 1000 \times 24 \times 400 \:  {cm}^{3} }}}

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: each  \: brick = length \times breadth \times height}}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: each  \: brick = 24 \times 12 \times 8 \:  {cm}^{3} }}}

So,

{\qquad \dashrightarrow{ \bf{Volume \:  of  \: bricks  \: required =  \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: bricks  \: required =  \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}

{\qquad \dashrightarrow{ \sf{Volume \:  of  \: bricks  \: required =   \bf \: 4166.6} }}

Therefore,

  • <u>The wall requires 4167 bricks. </u>

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Sindrei [870]

Answer:

Kindly check explanation

Step-by-step explanation:

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