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ddd [48]
2 years ago
12

Plumber A charges $60 an hour. Plumber B charges $40 to visit your home plus $55 for each hour. For how many hours will the tota

l cost for each plumber be the same? How much will that cost be? IDENTIFY THE SOLUTION POINT. HINT: Remember Initial Value = Y-intercept RATE = Slope *
Mathematics
1 answer:
GuDViN [60]2 years ago
6 0

Answer:

8 hours

$480

Step-by-step explanation:

Let us assume the hours be x

There should be two equations

For Plumber A = 60x

For Plumber B = 40 + 55x

Now in order to considered the cost to be the same we equate these two equations

60x = 40 + 55x

5x = 40

x = 8 hours

Now the total cost for plumber A is

= 480

And, the total cost for plumber B is

= 40 + 55(8)

= 480

hence, the total cost is $480

You might be interested in
-3x^2-5x+9=0 what is the value for a,b,and c
Tju [1.3M]

Answer:

a = -3  b = -5  c = 9

Step-by-step explanation:

A quadratic function is written in the form

ax^2 +bx +c =0

-3x^2-5x+9=0

a = -3  b = -5  c = 9

3 0
3 years ago
A bank loaned out $19,500, part of it at the rate of 11% annual interest, and the rest at 7% annual interest. The total interest
Morgarella [4.7K]

The amount loaned at the interest rate of 11% is $3000.

The amount loaned at the interest rate of 7% is $16,500

<h3>What are the linear equations that represent the question?
a + b = 19500 equation 1</h3>

0.11a + 0.07b = 1485 equation 2

Where:

a = amount loaned at the interest rate of 11%

b = = amount loaned at the interest rate of 7%

<h3>How much was loaned at 11% and 7%</h3>

In order to determine how much was loaned at 7%, take the following steps:

Multiply equation 1 by 0.11:

.11a + 0.11b = 2145 equation 3

Subtract equation 2 from equation 3:

0.04b = 660

Divide both sides by 0.04:

b = 16,500

Subtract 16,500 from 19,500 :

19,500 - 16,500 = $3000

To learn more about interest, please check: brainly.com/question/26164549

#SPJ1

7 0
2 years ago
PLEASE HELP ME ASAP ❤️
jek_recluse [69]

a^2-a-20

Answer :(x-5)(x+4)

3 0
3 years ago
X^-2+4x^-1+3=0 solve by making appropriate substitution
Alex

ANSWER

x =  - 1 \: or \: x =  -  \frac{1}{ 3}

EXPLANATION

The given equation is:

{x}^{ - 2}  + 4 {x}^{ - 1}  + 3 = 0

Recall that:

{a}^{ - m}  =  \frac{1}{ {a}^{m} }

\frac{1}{ {x}^{2} }  +  \frac{4}{x}  + 3 = 0

Or

{( \frac{1}{x} )}^{2}  + 4( \frac{1}{x} ) + 3 = 0

Let

u =  \frac{1}{x}

Our equation then becomes:

{u}^{2}  + 4u + 3 = 0

The factors of 3 that add up to 4 are:

{u}^{2}  + 3u + u + 3

u(u + 3) + 1(u + 3) = 0

(u + 1)(u + 3) = 0

u + 1 = 0 \: or \: u + 3 = 0

u =  - 1 \: or \: u =  - 3

This implies that:

\frac{1}{x}  =  - 1 \: or \:  \frac{1}{x}  =  - 3

x =  - 1 \: or \: x =  -  \frac{1}{ 3}

7 0
3 years ago
Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a U
creativ13 [48]

Answer:

Part 1) The square root of b^2-4ac

Part 2) 25

Step-by-step explanation:

Part 1.

In order to determine whether the quadratic equation can be solved by factoring, the square root of b^2-4ac has to be a real number, or else the quadratic can’t be factored. (Not a real number)

Part 2.

Plugging b, a, and c in,

We have 49-24 or 25.

4 0
3 years ago
Read 2 more answers
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