The art club had an election to select a president. 79 members voted in the election and 21

A pilot is flying a CRJ-900 from Phoenix, Arizona, to Louisville, Kentucky. The aircraft cannot take off or land if the temperat

ioda

We need to find an inequality that represents the possible landing or take of conditions of an aircraft, the required graph and one case where the inequality will be tested.

The required inequality is $-40$ .

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The pilot could not have taken off on June 1990, the temperature in Phoenix, Arizona.

Let the temperature be denoted by $x$

The temperature cannot be at or below $-40^{\circ}\text{F}$ , so

$x>-40$

The temperature cannot be at or above $118^{\circ}\text{F}$ , so

$x$

The inequality will be $-40$ .

In the graph it can be seen that all points between -40 and 118 falls in the shaded region but it will exclude the points -40 and 118.

The graph represents the allowable temperature range in which the aircraft can takeoff or land.

The temperature in June 1990 in Phoenix, Arizona was $122^{\circ}$ which is more than $118^{\circ}\text{F}$ .

Hence, the pilot could not have taken off on this day.

Learn more:

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4 0

2 years ago

ANSWER FAST MY DUDEZ!<br> What is the value of x in the equation <br> 1.8- 3.7x = 4.2x + 0.3

Inessa [10]

1.8- 3.7x = 4.2x + 0.3

Move 4.2x to the other side

Sign changes from +4.2x to -4.2x

1.8-3.7x-4.2x= 4.2x-4.2x+0.3

1.8-3.7x-4.2x= 0.3

1.8-7.9x= 0.3

Move 1.8 to the other side

Sign changes from +1.8 to -1.8

1.8-1.8-7.9x= 0.3-1.8

-7.9x= 0.3-1.8

-7.9x= -1.5

divide both sides by -7.9

-7.9/-7.9x= -1.5/-7.9

x= 0.18987341

Answer: x= 0.18987341

8 0

3 years ago

-2/3- (-3/4)<br><br> Simplify if needed <br> Brainliest <br><br> Also, 5/6+5/12

bazaltina [42]

Answer:

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}$

$\frac{5}{6} + \frac{5}{12} = \frac{5}{3}$

Step-by-step explanation:

Given

$-\frac{2}{3} - (-\frac{3}{4})$

Required

Solve:

$-\frac{2}{3} - (-\frac{3}{4})$

Open bracket

$-\frac{2}{3} - (-\frac{3}{4}) = -\frac{2}{3} +\frac{3}{4}$

Take LCM

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{-8+9}{12}$

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}$

$\frac{5}{6} + \frac{5}{12}$

Take LCM

$\frac{5}{6} + \frac{5}{12} = \frac{10+5}{12}$

$\frac{5}{6} + \frac{5}{12} = \frac{15}{12}$

Divide by 3/3

$\frac{5}{6} + \frac{5}{12} = \frac{5}{3}$

4 0

3 years ago

A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg

balu736 [363]

<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

$\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles$

Now we need to find length of race

$\texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles$

The race is 1.2 miles long

7 0

3 years ago

A student wanted to know the favorite lunch at a large high school with a closed campus. What is the first step in conducting a

Neko [114]

Answer:

Start By How many kids are in your hs

Step-by-step explanation:

Skskskkskskskksksks

6 0

3 years ago