Density = mass /volume of the body. mass = 10.88 g, volume of the liquid displaced= 49.4-43.5=5.9 ml.
density = 10.88/5.9=1.844 g/ml~1.84 g/ml
The volume displaced is exactly the same as that of the body (The Eureka fro Archimedes!)
When you work with molar mass, you solve for the quantity of ''Moles'' within the substance by converting Mass. The way you can tell the equation is balanced would be by knowing whether the moles were equivalent on both sides or not. Therefore, if they are equal, it is balanced considering you have the same amount of moles on each side of the equation.
Answer:
Physical change because even though gas formation was observed, the water was undergoing a state change, which means that its original properties are preserved.
Explanation:
Water boiling results in the physical state changing from solid to gaseous water. This moment can be called boiling or vaporizing, which is the change from liquid to gaseous state by heating water. Thus, the "Boiling Point" (PE) of a substance is the temperature at which that substance changes from liquid to gaseous state and, in the case of water, is 100 ° C. When the water reaches this temperature its physical change occurs because, despite the formation of gas, the water was undergoing a state change, which means that its original properties are preserved.
Answer is: 22,4 l of nitrogen.
Chemical reaction: 3H₂ + N₂ ⇄ 2NH₃.
V(NH₃) = 44,8 l = 44,8 dm³.
V(N₂) = ?
n(NH₃) = V(NH₃) ÷ Vm
n(NH₃) = 44,8 dm³ ÷ 22,4 dm³/mol
n(NH₃) = 2 mol.
from reaction: n(N₂) : n(NH₃) = 1 : 2
n(N₂) : 2 mol = 1 : 2
n(N₂) = 1 mol.
V(N₂) = n(N₂) · Vm
V(N₂) = 1 mol · 22,4 dm³/mol = 22,4 dm³.
Vm - molar volume
What is the specific heat of aluminum?
The specific heat of aluminum is 0.90J/g°C.
Given:
Heat absorbs = 677 J
Mass of the substance = 10 g
Initial temperature = 50°C
Final temperature = 125°C
Formula used:
Q = m x c x ΔT
which can also be written as,
Q = m x c x ( 
- 
)
where,
Q = heat absorbs
m = mass of a substance
c = heat capacity of aluminum
= Final temperature
= Initial temperature
Now, put all the values in the formula given above to get the specific heat of aluminum,
677g = (10g) x c x (125 - 50)°C
c = 0.9026 J/g°C
c = 0.90 J/g°C
Learn more about the specific heat of aluminum here,
brainly.com/question/13696634
#SPJ4
