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prohojiy [21]
3 years ago
8

Earth Science

Chemistry
1 answer:
KIM [24]3 years ago
6 0
The first one is D, the second one is A and the last is C and D
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Which choice best explains why a 1-kg sample of carbon and a 3-kg sample of carbon have similar properties?
prohojiy [21]
C is the answer to your prolblrm
6 0
3 years ago
In the image below, what is the name of the unstable molecule formed during the collision of A2 and B2?
miskamm [114]

Answer:

ig activated complex coz reactants were diaatomic molecules and they were stable initially later on we collided them so they broke into activated complex and they were highly unstable so that they bonded again with another ion!!!! so according to me B is correct OPTION!!

7 0
3 years ago
How many molecules are contained in a 7.20-g sample of dimethylmercury?
jekas [21]
The formula for dimethyl mercury is. HgC2H6 = (2x12) + (6x1) + (1x200.6) = 230.6 
So the molar mass of dimethyl mercury is 230.6 g/mol. 
Number of moles in 4.2g of dimethymercury = 4.2/ 230.6 = 0.0182 moles.  
1 moles of dimethymercury contains 6.02 * 10^23 
Hence 0.0182 moles contains X 
X = 0.0182 * 6.02 * 10^23 = 0.10952 * 10^23 = 1.0952 * 10^22.
3 0
3 years ago
Read 2 more answers
Must all four hydrogen atoms lie in the same plane? If not, what is the spatial relationship among them? Why?
RoseWind [281]

Answer:

We are considering an Allene molecule here, CH2CCH2. To answer your question, NO, they don't have to lie on the same plane. The spatial arrangement between them is that the center carbon that forms these pi bind in the left and right are PERPENDICULAR to each other.

Explanation:

We see here that The terminal carbons are sp2 hybridized, and form three σ-bonds each which means that each terminal carbon has one unhybridized p-orbital. The central carbon atom is sp hybridized, and forms two σ-bonds which means it has two unhybridized p-orbitals. For better understanding, let's call these two orbitals px and py. Summarily, These orbitals are perpendicular to each other

8 0
3 years ago
How many milliliters of a 0.275 M NaOH solution is required to react with 0.450 L of CO2 gas
padilas [110]

Volume of NaOH required to react = 145.5 ml

<h3>Further explanation</h3>

Reaction

CO₂(g) + 2 NaOH(aq)  ⇒Na₂CO₃(aq) + H₂O(l)

The volume of CO₂ : 0.45 L

mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

\tt mol~CO_2=\dfrac{0.45}{22.4}=0.02

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

\tt mol~NaOH=\dfrac{2}{1}\times 0.02=0.04

Then volume of NaOH :

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.04}{0.275}\\\\V=0.1455~L\rightarrow 145.5~mL

5 0
3 years ago
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