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Anarel [89]
3 years ago
7

Pls send the answer..pls...​

Physics
1 answer:
Sophie [7]3 years ago
4 0

Answer:

The fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

Explanation:

Given;

initial temperature of the liquid, t₁ = 76.3  +/-  0.4⁰C

final temperature of the liquid, t₂ = 67.7  +/-  0.3⁰C

The change in temperature of the liquid is calculated as;

Δt = t₂  -  t₁

Δt = (67.7 - 76.3)  +/-  (0.3 - 0.4)

Δt = (-8.6)  +/-  (-0.1)

Δt = 8.6 +/- 0.1 ⁰C

Therefore, the fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

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4 years ago
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7nadin3 [17]

Answer:

<h2>C. <u>0.55 m/s towards the right</u></h2>

Explanation:

Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

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AFTER COLLISION

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<u>x is the final velocity of the 0.25kg ball</u>

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0.15 * 0.75kgm/s = 0.1125 kgm/s

Using the law of conservation of momentum;

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0.25x = 0.25-0.1125

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<u></u>

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