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hodyreva [135]
3 years ago
15

a 0.24 kg blob of clay is thrown at a wall with an initial velocity of 19m/s. the clay comes to a stop against the wall in 82ms,

what is the average force experienced by the clay
Physics
1 answer:
leva [86]3 years ago
8 0

As per Newton's law we can say

F = \frac{dP}{dt}

here we can say

F = \frac{m(v_f - v_i)}{\delta t}

now we know that

v_f = 0

v_i = 19 m/s

\delta t = 82 ms

mass = 0.24 kg

now by above formula we will have

[tex]F = \frac{0.24(0 - 19)}{82*10^{-3}}[\tex]

so force on the wall is given by

F = 55.6 N

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The electric potential at the origin of an xy-coordinate system is 40 V. A -8.0-μC charge is brought from x = +∞ to that point.
vredina [299]

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Explanation:

Consider a point with an electrical charge of q. Assume that V is the electrical potential at the position of that charge. The electrical potential of that point charge will be equal to:

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Keep in mind that since both q and V might not be positive, the size of the electrical potential energy might not be positive, either.

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