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denpristay [2]
3 years ago
14

Which of the following solid fuels has the highest heating value?

Physics
1 answer:
Makovka662 [10]3 years ago
4 0
I wanna say its A . I could be wrong but im almost 100 percent sure that its A wood
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A circuit breaker is tripped when the
SCORPION-xisa [38]

Answer:

P= 15A x 120 V P= 1800 W

I believe, I hope this helps

Explanation:

7 0
3 years ago
You have just moved into a new apartment and are trying to arrange your bedroom. You would like to move your dresser of weight 3
jeka57 [31]

Answer:

W = 0J

Explanation:

The work done by the dresser is described as

W = f d (cos θ)

F has been given as the weight of this dresser. And it is 3500 N

d = 0 m

When you put these values into the equation

W = 3500 x 0 x cosθ

W = 0 J

This value tells us that the work done on this dresser is zero. No work has been done. Therefore the last option answers the question.

3 0
3 years ago
How does the current change if the resistance is doubled?
finlep [7]
The current will be divided by 2
7 0
3 years ago
A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of
garri49 [273]

Answer:

w_{0}=14

t=\frac{\pi }{14}

Explanation:

<u>Data</u>

<u>mass m= 100g</u>

<u>Length L= 5cm</u>

<u>we can use:</u>

<u>gm-kL= 0</u>

<u>divide both side by m</u>

<u>g - </u>\frac{kL}{m}<u>=0</u>

<u>where</u>

\frac{k}{m} = \frac{g}{L}

\frac{k}{m}=w_{0}^{2}

so now

w_{0}^{2} = \frac{9.8*100}{5}

w_{0}^{2}=\frac{980}{5}

w_{0}^{2}=196

square both side

w_{0}=\sqrt{196}

w_{0}=14

We can apply:

u(t)=Acoswt +Bsinwt

u(t)=Acos14t +Bsin14t

u(0)=0  where A=0

therefore

u(0) = Bsin14t  

u^{'}(0) = 10 ⇒ 10=14B ⇒ B=\frac{14}{10} B=\frac{5}{7}

so now u(t)=\frac{5}{7}sin14t

so t will be:

t=\frac{\pi }{14}

t=\frac{3.14}{14}

t=0.22 seconds

8 0
3 years ago
An object is dropped from 26 feet below the tip of the pinnacle atop a 702 ft tall building. The height h of the object after t
Dimas [21]

Answer:

6.5 seconds.

Explanation:

Given: h=-16t²+679

When the object reaches the ground, h=0.

∴ 0=-16t²+679

collecting like terms,

⇒ 16t²=679

Dividing both side of the equation by the coefficient of t² i.e 16

⇒ 16t²/16 = 679/16

⇒ t² = 42.25

taking the square root of both side of the equation.

⇒ √t² =√42.25

⇒ t = 6.5 seconds.

4 0
3 years ago
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