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vova2212 [387]
4 years ago
6

In which direction does a bag at rest move when a force of 20 newtons is applied from the right?

Physics
1 answer:
worty [1.4K]4 years ago
8 0

Answer:

in the direction of the applied force

Explanation:

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Does the gas have a well defined structure
dem82 [27]

What gas? Gas is an invisible form so I don't see how it would have a "defined structure".

6 0
3 years ago
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A wave with a period of 0.008 second has a frequency of
coldgirl [10]

The frequency of a wave is the reciprocal of its period.

A period of 0.008 sec means a frequency of

         1 / 0.008 sec  =  125 per sec .  (125 Hz)

8 0
3 years ago
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You hold a spherical salad bowl 50 cm in front of your face with the bottom of the bowl facing you. The salad bowl is made of po
nataly862011 [7]

Answer:

a) q = 39.29 cm ,  b)   h ’= - 3.929 cm  the image is inverted  and REAL

Explanation:

For this exercise we will use the equation of the constructor

          1 / f = 1 / p + 1 / q

where f is the focal length of the salad bowl, p and q are the distance to the object and the image

The metal salad bowl behaves like a mirror, so its focal length is

           f = R / 2

           f = 44/2

           f = 22 cm

a) Suppose that the distance to the object is p = 50 cm, let's find the distance to the image

           1 / q = 1 / f  - 1 / p

           1 / q = 1/22 - 1/50

           1 / q = 0.0254

            q = 39.29 cm

b) to calculate the size of the image we use the equation of magnification

           m = h’/ h = - q / p

            h ’= - q / p h

            h ’= - 39.29 / 50 5

            h ’= - 3.929 cm

the negative sign means that the image is inverted

as the rays of light pass through the image this is REAL

4 0
4 years ago
2. When the birth rate is larger than the death rate in any given period the population will
stich3 [128]
B if not please comment back .
8 0
3 years ago
A 8.0 µF capacitor is initially connected to a 2.0 V battery. Once the capacitor is fully charged the battery is removed and a 6
aalyn [17]

Answer:

I = 0.451 amp

Explanation:

given,

C = 8.0 µF

V = 2 V

resistor connected between two terminal = 6 Ω

current flowing through resistor = 13 µsec

Q = CV

Q = 8 x 2

Q = 16 µC                              

for an RC discharge circuit

V = V_0e^{-\dfrac{t}{RC}}

I = \dfrac{-Q_0}{RC}e^{-\dfrac{t}{RC}}

t =  13 µsec

I = \dfrac{-16}{6\times 2}e^{-\dfrac{13}{6\times 2}}

I = 0.451 amp

neglecting  -ve sign just to show direction.

3 0
3 years ago
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