8) What is the area of parallelogram RSTU? *

Elina [12.6K]

Answer: 7+0.7+0.05

Since 7 is in the ones place it goes in front of the decimal. .7 is in the tenth place because it's behind the decimal. .05 is also behind the decimal so it's in the hundredths place.

4 0

4 years ago

Directions: Simplify the following monomials (if possible).

MakcuM [25]

13. 17y² - 22y

14. 9m²n+7mn²

15. 11y²

16. 8x²y

I'm not 100% sure if these are all correct, so please forgive me if I'm wrong.

Hopefully this helps, and please consider marking branliest.

5 0

3 years ago

Suppose that the population P(t) of a country satisfies the differential equation dP/dt = kP (600 - P) with k constant. Its pop

jeka94

Answer:

The country's population for the year 2030 is 368.8 million.

Step-by-step explanation:

The differential equation is:

$\frac{dP}{dt}=kP(600 - P)\\\frac{dP}{P(600 - P)} =kdt$

Integrate the differential equation to determine the equation of P in terms of <em>t</em> as follows:

$\int\limits {\frac{1}{P(600-P)} } \, dP =k\int\limits {1} \, dt \\(\frac{1}{600} )[(\int\limits {\frac{1}{P} } \, dP) - (\int\limits {\frac{}{600-P} } \, dP)]=k\int\limits {1} \, dt\\\ln P-\ln (600-P)=600kt+C\\\ln (\frac{P}{600-P} )=600kt+C\\\frac{P}{600-P} = Ce^{600kt}$

At <em>t</em> = 0 the value of <em>P</em> is 300 million.

Determine the value of constant C as follows:

$\frac{P}{600-P} = Ce^{600kt}\\\frac{300}{600-300}=Ce^{600\times0\times k}\\\frac{1}{300} =C\times1\\C=\frac{1}{300}$

It is provided that the population growth rate is 1 million per year.

Then for the year 1961, the population is: P (1) = 301

Then $\frac{dP}{dt}=1$ .

Determine <em>k</em> as follows:

$\frac{dP}{dt}=kP(600 - P)\\1=k\times300(600-300)\\k=\frac{1}{90000}$

For the year 2030, P (2030) = P (70).

Determine the value of P (70) as follows:

$\frac{P(70)}{600-P(70)} = \frac{1}{300} e^{\frac{600\times 70}{90000}}\\\frac{P(70)}{600-P(70)} =1.595\\P(70)=957-1.595P(70)\\2.595P(70)=957\\P(70)=368.786$

Thus, the country's population for the year 2030 is 368.8 million.

3 0

3 years ago

Persons A and B are at the beach, their eyes are 5 ft and 6 ft, respectively, above sea level. How many miles farther out is Per

Marysya12 [62]

Answer:

The radius of the earth is something like 4000 miles= about 20,000,000 feet. (Look up the exact radius of the earth to calculate the correct number yourself, I'm too lazy!)

The horizon is where you're looking at a tangent to the earth's surface. Since the tangent to a circle is perpendicular to the radius (if we assume the earth is a perfect sphere), we can set up a right angled triangle:

H...P

.

C

Where C is the centre of the earth, H is the horizon, and P is the person. CH = 20,000,000 feet. CP = 20,000,005 feet (in the case of the 5' person, that'd be me :) And there is a right angle at H.

So using Pythagoras' theorem, if d = PH, then:

d^2 = 20,000,005^2 - 20,000,000^2

=> d^2 = 200,000,025

=> d = 14142 feet (just under 3 miles)

For a 6' person:

d^2 = 20,000,006^2 - 20,000,000^2

=> d^2 = 240,000,036

=> d = 15491 feet

So the difference is 1349 feet or 0.256 miles

Repeat this exercise with the real radius of the earth (in feet) to get the correct answer, but it'll be pretty close to what I've given here

4 0

3 years ago

16 is 25% of what number?

ivann1987 [24]

16 is 25% of 64.

<h3>What are percentages?</h3>

Percentage is the fraction of an amount that is usually expressed as a number out of hundred. Percentages are a measure of frequency.

In order to determine the number, divide 16 by 25%

16 / 25%

16 / 0.25 = 64

To learn more about percentages, please check: brainly.com/question/25764815

8 0

3 years ago

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