Answer:
B. tablespoon
Explanation:
Considering the question given, a mole of water is small compare to the options given from the question aside the table spoon.
A mole of water is just 18g and that's equivalent to 18 mL.
18 mL of water will fill a table spoon but not a cup which is about 237mL. The wheel barrow and gallon bucket have larger volumes of which 18 mL of water will never fill them.
So, a mole of water can successfully fill a table spoon.
Given:
V1 = initial velocity = 24 m/s
a = acceleration = 2.0 m/s^2
s = time = 8 s
V2 = final velocity = ?
For linear-motion problems with those given terms, the following formula is used:
V2 = V1 + as
Substituting the given values:
V2 = 24 + 2(8)
V2 = 24 + 16
V2 = 40 m/s
Therefore the car will have a speed of 40 m/s as it leaves the tunnel.
Answer:
![6.99535\times 10^{-6}\ V/m](https://tex.z-dn.net/?f=6.99535%5Ctimes%2010%5E%7B-6%7D%5C%20V%2Fm)
Explanation:
P = Power Output = 1000 W
r = Radius = 35000000 m
= Permittivity of free space = ![8.85\times 10^{-12}\ F/m](https://tex.z-dn.net/?f=8.85%5Ctimes%2010%5E%7B-12%7D%5C%20F%2Fm)
c = Speed of light = ![3\times 10^8\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8%5C%20m%2Fs)
Intensity of Electric radiation is given by
![I=\dfrac{P}{A}\\\Rightarrow I=\dfrac{P}{4\pi r^2}\\\Rightarrow I=\dfrac{1000}{4\pi\times 35000000^2}\ W/m^2](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BP%7D%7BA%7D%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7BP%7D%7B4%5Cpi%20r%5E2%7D%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7B1000%7D%7B4%5Cpi%5Ctimes%2035000000%5E2%7D%5C%20W%2Fm%5E2)
Intensity of Electric radiation is given by
![I=\dfrac{1}{2}c\epsilon_0E_0\\\Rightarrow E_0=\sqrt{\dfrac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\dfrac{2\times \dfrac{1000}{4\pi\times 35000000^2}}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=6.99535\times 10^{-6}\ V/m](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B1%7D%7B2%7Dc%5Cepsilon_0E_0%5C%5C%5CRightarrow%20E_0%3D%5Csqrt%7B%5Cdfrac%7B2I%7D%7Bc%5Cepsilon_0%7D%7D%5C%5C%5CRightarrow%20E_0%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%20%5Cdfrac%7B1000%7D%7B4%5Cpi%5Ctimes%2035000000%5E2%7D%7D%7B3%5Ctimes%2010%5E8%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%7D%7D%5C%5C%5CRightarrow%20E_0%3D6.99535%5Ctimes%2010%5E%7B-6%7D%5C%20V%2Fm)
The amplitude of the electric field vector is ![6.99535\times 10^{-6}\ V/m](https://tex.z-dn.net/?f=6.99535%5Ctimes%2010%5E%7B-6%7D%5C%20V%2Fm)
<u>Answer:</u>
At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom
<u>Explanation:</u>
We have equation of motion ,
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Considering the horizontal motion of paint ball
Distance traveled during time t = 4 cm
Initial velocity = u m/s
Acceleration = 0 ![m/s^2](https://tex.z-dn.net/?f=m%2Fs%5E2)
So ![4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}](https://tex.z-dn.net/?f=4%20%3D%20u%2At%2B%5Cfrac%7B1%7D%7B2%7D%20%2A0%2At%5E2%5C%5C%20%5C%5C%20u%20%3D%20%5Cfrac%7B4%7D%7Bt%7D)
Now at time 2t,
![S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm](https://tex.z-dn.net/?f=S%3D%20u%2A2t%2B%5Cfrac%7B1%7D%7B2%7D%20%2A0%2A%282t%29%5E2%5C%5C%20%5C%5C%3D%5Cfrac%7B4%7D%7Bt%7D%20%2A2t%5C%5C%20%5C%5C%20%3D8cm)
So horizontal distance traveled in time 2t = 8 cm to the right
Now considering the vertical motion of paint ball
Distance traveled during time t = 4 cm
Initial velocity = 0 m/s
Acceleration = -g ![m/s^2](https://tex.z-dn.net/?f=m%2Fs%5E2)
![4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}](https://tex.z-dn.net/?f=4%3D0%2At-%5Cfrac%7B1%7D%7B2%7D%20%2Ag%2At%5E2%5C%5C%20%5C%5C%20t%5E2%3D%5Cfrac%7B-8%7D%7Bg%7D)
At time 2t,
![S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm](https://tex.z-dn.net/?f=S%3D0%2A2t-%5Cfrac%7B1%7D%7B2%7D%20%2Ag%2A%282t%29%5E2%5C%5C%20%5C%5C%20%3D-%5Cfrac%7B1%7D%7B2%7D%20%2Ag%2A4%2A%5Cfrac%7B-8%7D%7Bg%7D%5C%5C%20%5C%5C%20%3D16%20cm)
So vertical distance traveled in time 2t = 16 cm to the bottom
Answer: It is done to prevent the necessary compound from solidifying along with the debasements. It expels any insoluble pollutions from the appropriate response (as opposed to separating the predetermined item). With since quite a while ago stemmed channels, the gems kick off inside the progression because the arrangement cools, obstructing the pipe. utilizing a stemless channel keeps this from occurring.
Explanation: