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SCORPION-xisa [38]
3 years ago
11

A person plugs a power cord into an electrical outlet in the wall. The power cord is covered in black rubber. Which statement is

an accurate description of the materials?(1 point)
Electrons move through air when the cord is a few inches from the outlet.

Electrons would easily move through the person if there was no rubber around the wire.

Electrons would not move through the wire if there was no rubber around the wire.

Electrons easily move through the rubber around the wire.
Chemistry
1 answer:
rjkz [21]3 years ago
4 0

Answer:

Electrons would easily move through the person if there was no rubber around the wire.

Explanation:

The black rubber material is an insulator and will not allow the conduction of heat or electrical current through it. Electrical currents are generated by the movement of electrons through materials.

<em>Hence, if there was no rubber covering around the power cord, the person that plugged-in the power cord would have experienced electric shock because electrons would easily move through him/her from the wire. </em>

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Why do plants need sap?
Nadya [2.5K]
Plants don't need sap. They make it like Maple trees.
8 0
3 years ago
Read 2 more answers
A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )
Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g)   (1)

The reaction rate of equation (1) is given by:

rate = k*[O_{3}][NO]     (2)

<u>We have:</u>

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s  

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

\frac{\Delta[NO_{2}]}{\Delta t} = rate

\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!                                

5 0
3 years ago
You wish to make a 0.375 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid
cluponka [151]

We need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

You are performing a dilution of HBr going from a concentration of 12M to 0.335M, and you want to end up with a final volume of 75 ml of the dilute solution.

Consider the dilution formula: M1V1 = M2V2.

The basis behind this formula is that the number of moles of the acid before and after the dilution must remain constant.

M1 = the molarity of the stock solution,

M2 = the molarity of the diluted solution,

V2 = the final volume of the diluted solution.

In this case, we need to determine V1, which is the volume of the stock solution used to prepare the diluted sample. With this knowledge, we can plug our numbers into the equation and we obtain the following:

(12 mol/L)*V1 = (0.335mol/L)*(0.075L).

Keeping in mind that molarity is the moles of a substance in one liter of solution, we will use mol/L instead of M. By doing this, we are reminded that in order to use this equation, we must convert 75 mL into units of liters.

After rearranging the equation and solving for V1, we find that V1 = 0.00209L.

Finally, we must convert back from liters to mL by multiplying the final answer by 1000.

This way we end up with V1 = 2.09 mL.

This means that we need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

Learn more about molarity here: brainly.com/question/23243759

#SPJ4

3 0
2 years ago
What is your calculated density of water at R.T.?
Alekssandra [29.7K]
The mass of 40 mL of water is 40 grams. Since D = m/v and mL = cm3, the density of water is 1 g/cm3. Choose a volume between 1 and 100 mL. Use your graph to find the mass.
3 0
3 years ago
Hydrogen (H), oxygen (O), and Nitrogen (N) are all examples of which of the following?
Llana [10]

Answer:

All are correct

Explanation:

This might be a little deceptive.  The question shows H, O and N which would designate ELEMENTS.

However, all of these can also be considered compounds and molecules as well.  BUT, they are H₂, O₂ and N₂ when they are molecules and compounds.

So it depends on the whether the question is being literal or not.

8 0
3 years ago
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