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soldi70 [24.7K]
3 years ago
12

Please help if you can !

Chemistry
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

7630

Explanation:

8090 [49]3 years ago
6 0

eAnswer:

Explanation:

Math

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Find the volume of an object that has a mass of 20g and density of 184 glcm
expeople1 [14]
Volume= Mass/ Density= 20/184
= 0.108 cubic cm
8 0
3 years ago
When 100 mL of 0.200 M NaCl(aq) and 100 mL of 0.200 M AgNO3(aq), both at 21.9 °C, are mixed in a coffee cup calorimeter, the tem
masya89 [10]

Answer:

There is 1.3 kJ heat produced(released)

Explanation:

<u>Step 1:</u> Data given

Volume of a 0.200 M Nacl solution = 100 mL = 0.1 L

Volume of a 0.200 M AgNO3 solution = 100 mL = 0.1 L

Initial temperature = 21.9 °C

Final temperature = 23.5 °C

Solid AgCl will be formed

<u>Step 2</u>: The balanced equation:

AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

AgCl(s) + NaNO3(aq) → Na+(aq) + NO3-(aq) + AgCl(s)

<u>Step 3:</u> Define the formula

Pressure is constant.  → the heat evolved from the reaction is equivalent to the enthalpy of reaction.  

Q=m*c*ΔT

⇒ Q = the heat transfer (in joule)

⇒ m =the mass (in grams)

⇒ c= the heat capacity (J/g°C)

⇒ ΔT = Change in temperature = T2- T1

Step 4: Calculate heat

Let's vonsider the density the same as the density of water (1g/mL)

Mass = volume * density

Mass = 200 mL * 1g/mL

Mass = 200 grams

Q= m*c*ΔT

⇒ m = 200 grams

⇒ c = the heat capacity (let's consider the heat capacity of water) = 4.184 J/g°C

⇒ ΔT = 23.5 -21.9 = 1.6°C

Q = 200 * 4.184 * 1.6 = 1338 .9 J = 1.3 kJ

There is 1.3 kJ heat produced(released)

Therefore, we assumed no heat is absorbed by the calorimeter, no heat is exchanged between the  calorimeter and its surroundings, and the specific heat and mass of the solution are the same as those for  water (1g/mL and 4.184 J/g°C)

7 0
3 years ago
What is the mass of and object with a volume of 100 cm3 and a density of 10 g/cm3?
nadezda [96]

Answer:

1000 g

Explanation:

d = m/v

We are given d: 10g/cm3

and v: 100cm3

Plug them into the equation to get 10 = m/100

Then, cross multiply 10x100 to get mass which is: 1000g

4 0
3 years ago
The sediment deposited by debris-laden melt water is called _______.
AlekseyPX
Answer: ( Outwash )
hope this helps!
8 0
3 years ago
2.3 x 10²¹ particles H = __________ mol H (round to the nearest thousandth)
Natalka [10]

Taking into account the definition of avogadro's number, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.

<h3>Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>This case</h3>

Then you can apply the following rule of three: if 6.023×10²³ particles are contained in 1 mole of H, then 2.3×10²¹ particles are contained in how many moles of H?

amount of moles of H= (2.3×10²¹ particles × 1 mole)÷ 6.023×10²³ particles

<u><em>amount of moles of H= 3.82×10⁻³ moles</em></u>

Finally, 3.82×10⁻³ moles of H are 2.3×10²¹ particles of H.

Learn more about Avogadro's Number:

<u>brainly.com/question/11907018?referrer=searchResults </u>

<u>brainly.com/question/1445383?referrer=searchResults </u>

<u>brainly.com/question/1528951?referrer=searchResults</u>

7 0
2 years ago
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