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Leni [432]
3 years ago
10

Develop a demonstration to show how mass is not the same thing as weight

Chemistry
1 answer:
pychu [463]3 years ago
4 0

This is more of a physics explanation, but here we go.

Mass is a measure of how much "matter" is in an object. Weight is the force applied onto an object by gravity. Weight itself can be related to mass like this:

f_g = mg

where g is a gravitational constant. For our purposes, it's defined by whatever planet you are on. Following this, we can demonstrate that mass is NOT the same thing as weight if we take two objects of the same mass and put them on different planets.

Let E refer to Earth and F refer to Mars

g_E = 9.81 m/s^2\\g_F = 3.711 m/s^2

Following this, we can see clearly that weight is not the same as mass:

m*9.81 : m*3.711 \\\int\limits^a_b {x} \, dx 9.81 \neq 3.711\\f_g E \neq f_g F\\

If weight was the same thing as mass, the two values would be the same, as the mass of the two objects is the same. But since weight is defined in the context of gravity, they are not.

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Write the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate. 2
Margarita [4]
<span>Benzoin<span> is an organic compound with the formula PhCH(OH)C(O)Ph. It is a hydroxy ketone attached to two phenyl groups.</span><span>

To answer your question, </span><span>the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate is:

</span>2Ph-C(OH)-C(O)-Ph+NH4NO3 --> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.</span>

<span>
</span><span>I hope this helps and if you have any further questions, please don’t hesitate to ask again.</span>

7 0
3 years ago
If the volume of a cylinder is reduced from 8.0 liters to 4.0 liters, the pressure of the gas in the cylinder will change from 7
Elza [17]

Answer:

P₂ = 140 KPa

Explanation:

Given data:

Initial volume = 8.0 L

Final volume = 4.0 L

Initial pressure = 70 KPa

Final pressure = ?

Solution:

According to Boyle's law

P₁V₁ = P₂V₂

P₂ = P₁V₁  / V₂

P₂ = 70 KPa ×8.0 L/4.0 L

P₂ = 560 KPa .L / 4.0 L

P₂ = 140 KPa

6 0
3 years ago
Light acts like a
8_murik_8 [283]
Particle
wave are the words you're looking for to fill in the blanks
7 0
3 years ago
Read 2 more answers
The work function for metallic magnesium is 3.68 eV. Calculate the velocity in km/s for electrons ejected from a metallic magnes
Lemur [1.5K]

Answer:

v = 301.62 km/s

Explanation:

Given that:

The work function of the magnesium = 3.68 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, work function = 3.68\times 1.6022\times 10^{-19}\ J=5.8961\times 10^{-19}\ J

Using the equation for photoelectric effect as:

E=\psi _0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

Applying the equation as:

\frac {h\times c}{\lambda}=\psi _0+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

m is the mass of electron having value 9.11\times 10^{-31}\ kg

\lambda is the wavelength of the light being bombarded

\psi _0=Work\ function

v is the velocity of electron

Given, \lambda=315\ nm=315\times 10^{-9}\ m

Thus, applying values as:

\frac{6.626\times 10^{-34}\times 3\times 10^8}{315\times 10^{-9}}=5.8961\times 10^{-19}+\frac{1}{2}\times 9.11\times 10^{-31}\times v^2

5.8961\times \:10^{-19}+\frac{1}{2}\times \:9.11\times \:10^{-31}v^2=\frac{6.626\times \:10^{-34}\times \:3\times \:10^8}{315\times \:10^{-9}}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=6.31047619\times 10^{-19}-5.8961\times 10^{-19}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=0.41437619\times 10^{-19}

v^2=0.0909717212\times 10^{12}

v = 3.0162 × 10⁵ m/s

Also, 1 m = 0.001 km

So, v = 301.62 km/s

8 0
3 years ago
. For 2A + 3B → 2C, [A]0 = 0.15, [B]0 = 0.12, and the initial rate is 0.10 mol/Ls. Assume that the reaction described above is f
damaskus [11]

Answer:

0.25

Explanation:

The rate law for the reaction:

2A(g) + 2B(g) ⟶ 2A(g) + 2B(g)

has been determined to be rate = k[2A]2[2B]. What are the orders with respect to each reactant, and what is the overall order of the reaction?

Answer:

order in 2A= 0.15; order in 2B = 0.10; overall order = 0.25

4 0
3 years ago
Read 2 more answers
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