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Verdich [7]
3 years ago
7

An airplane flies with a constant speed of 640km/h. how far can it travel in 45 minutes?

Physics
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

the answer is 483.75 I believe

You might be interested in
What is the kinetic energy of a 145 g baseball moving at 42 m/s?
klio [65]
Answer:
Kinetic energy = 127.89 Joules

Explanation:
Kinetic energy is calculated using the following rule:
KE = (1/2)*v* v^2
Where:
m is the mass = 145 g = 0.145 kg
v is the velocity = 42 m/sec

Substitute in the above equation to get the kinetic energy as follows:
KE = (0.5)(0.145)(42)^2
Kinetic energy = 127.89 Joules

Hope this helps :)
8 0
3 years ago
Which term means the weight of air measured in units of force per area?
Norma-Jean [14]
Force per area is pressure so I think the answer would be air pressure. Relative pressure sounds like it is a measure of pressure relative to something else.
3 0
3 years ago
Which of the following atoms contain a nucleus with no neutrons.
Aleksandr-060686 [28]

Answer:

Hydrogen

Explanation:

(H) atom does not have any neutrons in it's tiny nucleus.

7 0
3 years ago
Read 2 more answers
Which data storage device will not have its data scrambled by a magnet?
frutty [35]
Solid state drives. Hard disk drives use a rotating platter that has data written by magnets, so having a strong magnet near one will corrupt its data. Solid state drives on the other hand, use electrical switches and no mechanical pieces. They are also generally faster than hard drives.
6 0
4 years ago
Read 2 more answers
A 0.091-in-diameter electrical wire at 90°F is covered by 0.02-in-thick plastic insulation (k = 0.075 Btu/h·ft·°F). The wire is
olya-2409 [2.1K]

Answer:

The critical radius of the plastic insulation is 0.72 inches.

Explanation:

Given that,

Diameter = 0.091 in

Thickness = 0.02 in

Initial temperature = 90°F

Final temperature = 50°F

Heat transfer coefficient = 2.5 Btu/h.ft²°F

Material conductivity = 0.075 Btu/h.ft °F

We need to calculate the critical radius of the plastic insulation

Using formula of critical radius

r_{cr}=\dfrac{2K}{h}

Where, k = Material conductivity

h = Heat transfer coefficient

Put the value into the formula

r_{cr}=\dfrac{2\times0.075}{2.5}

r_{cr}=0.06\ ft

r_{cr}=0.72\ inches

Hence, The critical radius of the plastic insulation is 0.72 inches.

4 0
3 years ago
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