Answer:
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Answer:
a=7.384 m/s^2
Explanation:
let T be the tension in the string, m= mass
and a= acceleration
from the FBD in the attachment we can write
Tcos37°= mg
Tsin37° =ma
dividing both the equations we get
tan37° =a/g
therefore a=g×tan37°
a= 9.81×0.7535 = 7.384 m/s^2
the magnitude of the acceleration a of the train = 7.384 m/s^2
Answer:
b) in a direction that makes its potential energy decrease.
Explanation:
- As the electric field has the direction that would take a positive test charge under its sole influence, the positive test charge, will have an increase in its kinetic energy.
- Due to the conservation of energy, in absence of non-conservative forces, this increment must be equal and opposite to the change in electric potential energy, which will be always negative, independent of the sign of the charge.