Please help me it's just one question!

Methylene chloride (CH2Cl2) has fewer chlorine atoms than chloroform (CHCl3). Nevertheless, methylene chloride has a larger mole

icang [17]

Answer:

Explanation has been given below.

Explanation:

Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
Chloroform has three C-Cl bonds and methylene chloride has two C-Cl bonds. Therefore opposite induction is higher for chloroform resulting it's lower dipole moment.

3 0

3 years ago

Calculate the mass of khc8h4o4 that reacts with 15 ml of the naoh solution

dlinn [17]

The balanced chemical reaction would be:

KHC8H4O4<span> (aq) + </span>NaOH<span> (aq) → NaKC8H4O4 (aq) + H2O.

The concentration of the NaOH is equal 0.1 M. We use this and the volume given above to determine the mass of KH</span>C8H4O4. We do as follows:

0.1 mol / L NaOH (.015 L) ( 1 mol KHC8H4O4 / 1 mol NaOH) (204 g / 1 mol) = 0.306 g KHC8H4O4

6 0

3 years ago

Need the answer asap giving 30 points.

finlep [7]

what are teacher teaching you

5 0

3 years ago

What has mass and takes up space

I am Lyosha [343]

Answer:

matter

Explanation:

everything around us

6 0

3 years ago

If 30.0 ml of 0.150 m aqueous sodium hydroxide is mixed with 30.0 ml of 0.150 m aqueous hydrochloric acid in a calorimeter at an

umka21 [38]

Answer : As given in the question the concentration of acid and base are in equimolar proportion so,

the simple net ionic reaction that the system is undergoing can be given as,
$H^{+} _{(aq.)} + OH^{-} _{(aq.)} ----\ \textgreater \ H_{2} O + heat$

we can now calculate the total number of moles reacting in the species as,

(30 mL) X (1L/1000ML) X 0.150 moles = $4.5 X 10 ^{-3}$ moles.

Now, we know the specific heat of water as 4.186 J/g °C.

Now considering the total volume of the product as 60 mL or 60 g (as it is water it can be g or mL) hence, ΔC is 2.5 C.

Now converting these into joules = 4.186 J/g °C X 2.5 X 60 = 627.9 Joules.

On dividing this we get 627.9 Joules / $4.5 X 10 ^{-3}$ moles = 140 KiloJoules/mole.

So the answer is 140 KJ/M.

3 0

3 years ago