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MrRissso [65]
3 years ago
10

(35 POINTSSSS)help plzzz do as much as u can

Chemistry
1 answer:
grigory [225]3 years ago
5 0

Answer:

the required anions and cations are :

<h3> cation / anion</h3>

  • Al 3+ / Cl -
  • Al 3+ / PO3-
  • Be 2+ / I -
  • Sr 2+ / F -
  • K + / N 3-
  • Na + / S 2-
  • Ca 2+ / Cl -
  • Na + / Br2-
  • Mg 2+ / S 2-
  • Al 3+ / O 2-
  • Li + / P 3-
  • Cs + / N 3-
  • K + / I -
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m=1.325gNa_2CO_3

Explanation:

Hello,

In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:

eq-g=0.5eq-g/L*0.050L=0.025eq-g

Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:

mol=0.025eq-gNa_2CO_3*\frac{1molNa_2CO_3}{2eq-gNa_2CO_3}\\ \\mol=0.0125molNa_2CO_3

Finally, the mass is computed by using its molar mass (106 g/mol)

m=0.0125molNa_2CO_3*\frac{106gNa_2CO_3}{1molNa_2CO_3} \\\\m=1.325gNa_2CO_3

Regards.

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