There is a box on the floor. The following forces are being applied to it:
2 answers:
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Explanation:
Let us assume that the given cylinder is 2.6 cm wide and its height is 3.1 cm. And, when piston is pushed down then the steady force is equal to 15 N.
Now, radius of the cylinder will be as follows.
r =
=
= 1.3 cm
or, = 0.013 m (as 1 m = 100 cm)
As, area of cylinder =
=
=
Relation between pressure and force is as follows.
Pressure =
=
= 25996
Since, 1 = 1 Pa (as 1 kPa = 1000 Pa)
Therefore, P = 25996
= 25.99 kPa
= 26 kPa (approx)
Thus, we can conclude that pressure of the gas inside the cylinder is 26 kPa.
We have that the see-saw will be balance if a weight of is added to Nural's side of the see-saw
From the Question we are told that
Wan’s mass is
Nurul’s mass is
Generally
The Will be balance when the weight on both sides of the see-saw are equal
In conclusion
The see-saw will be balance if a weight of is added to Nural's side of the see-saw
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