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Pepsi [2]
2 years ago
9

A 7.40-kg object initially has 347 J of gravitational potential energy. Then an elevator lifts the object a distance of 20.6 m a

bove its previous position. How much work did the elevator perform on the object?
Physics
1 answer:
storchak [24]2 years ago
6 0

Answer:

W = 1493.9 J = 1.49 KJ

Explanation:

The work done by the elevator on the object will be equal to the gain in is potential energy:

W = ΔP.E

W = mgΔh

where,

W = Work = ?

m = mass of object = 7.4 kg

g = 9.8 m/s²

Δh = gain in height = 20.6 m

Therefore,

W = (7.4 kg)(9.8 m/s²)(20.6 m)

<u>W = 1493.9 J = 1.49 KJ</u>

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Akimi4 [234]

Answer:

Ocean currents act as conveyer belts of warm and cold water, sending heat toward the polar regions and helping tropical areas cool off, thus influencing both weather and climate.

Explanation:

5 0
2 years ago
Read 2 more answers
What is the difference in
maxonik [38]
<h3>Answer:</h3>

209.236 kg · m/s

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Physics</u>

<u>Momentum</u>

Momentum Formula: P = mv

  • P is momentum (in kg · m/s)
  • m is mass (in kg)
  • v is velocity (in m/s)
<h3>Explanation:</h3>

<u>Step 1: Define</u>

m₁ = 87.2 kg

v₁ = 2.87 m/s

m₂ = 0.0520 kg

v₂ = 789 m/s

<u>Step 2: Find Momentums</u>

<em>Football Player</em>

  1. Substitute [MF]:                    P = (87.2 kg)(2.87 m/s)
  2. Multiply:                                P = 250.264 kg · m/s

<em>Bullet</em>

  1. Substitute [MF]:                    P = (0.0520 kg)(789 m/s)
  2. Multiply:                                P = 41.028 kg · m/s

<u>Step 3: Find difference</u>

  1. Define equation:                    P₁ - P₂
  2. Substitute:                              250.264 kg · m/s - 41.028 kg · m/s
  3. Subtract:                                 209.236 kg · m/s
3 0
3 years ago
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An airplane is flying in a horizontal circle at a speed of 92.1 m/s. The 55.6 kg pilot does not want his radial acceleration to
Fudgin [204]

Answer:

 r = 102.43 m

Explanation:

Newton's second law for this case is

              F = ma

Where the acceleration is centripetal

            a = v² / r

            r = v² / a

They indicate that the radial acceleration is 8.45 g

           r = v² / 8.45 g.

           r = 92.1² / 8.45 9.8

           r = 102.43 m

7 0
3 years ago
The maximum amount of pulling force a truck can apply when driving on
kupik [55]
C the correct but not sure?
5 0
3 years ago
A basketball star exerts a force of 3225 n (average value) upon the gym floor in order to accelerate his 76.5-kg body upward. de
ryzh [129]
F = m . g  = 76.5 x 9..8 = 749.7
Net Force = 3225 - 749.7 = 2475.3

F = m.a
2475.3 = 76.5 a

a  = 32.35



V = at + v1
V = at + 0
V = 32.35 x 0.15
V = 4.8525

Hope this helps

8 0
3 years ago
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