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Novosadov [1.4K]
3 years ago
15

Prepare a journal entry for the purchase of office equipment on February 19 for $31,700, paying $7,600 cash and the remainder on

account. Refer to the chart of accounts for the exact wording of the account titles. CNOW journals do not use lines for journal explanations. Every line on a journal page is used for debit or credit entries. CNOW journals will automatically indent a credit entry when a credit amount is entered.
Business
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

Dr Office equipment 31,700

Cr cash 7,600

Cr Accounts payable 24,100

Explanation:

Preparation of the journal entry for the purchase of office equipment on February 19

Based on the information given the if asset was purchased on February 19 for the amount of $31,700 in which the company paid the amount of $7,600 cash and the remainder on account which means that the journal entry will be:

February 19

Dr Office equipment 31,700

Cr cash 7,600

Cr Accounts payable 24,100

(31,700-7,600)

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Answer:

interest expense 3,000 debit

   interest payable       3000 credit

Explanation:

We will recognize the accrued interest for the period Nov 1st to Dec 31th

 principal   x   rate     x    time

  120,000   x 11%/12   x 3 months = 3,000

We divide the rate by 12 as there is express as annual rate and we need to match with time, which is months.

The entry will recognize interest expense for 3,000

and interest payable for 3,000

3 0
3 years ago
A car dealer who sells only late-model luxury cars recently hired a new salesman and believes that this salesman is selling at l
Natasha2012 [34]

Answer:

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

Explanation:

Data given and notation      

\bar X=5000 represent the sample mean      

s=800 represent the standard deviation for the sample      

n=16 sample size      

\mu_o =5600 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:      

Null hypothesis:\mu \geq 5600      

Alternative hypothesis:\mu < 5600      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

4 0
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2 years ago
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Answer:

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