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natali 33 [55]
3 years ago
7

1. A beaker holding 1.5 litres of water is placed in a temperature-controlled room so that 120 mL of

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

Answer:

<em>Oi</em><em> </em><em>tudo</em><em> </em><em>bem</em><em>?</em><em> </em>

<em>meu</em><em> </em><em>nome</em><em> </em><em>é</em><em> </em><em>Ana</em><em> </em><em>Kesia</em><em>,</em><em> </em><em>e</em><em> </em><em>qual</em><em> </em><em>é</em><em> </em><em>o</em><em> </em><em>seu</em><em> </em><em>nome</em><em> </em><em>também</em><em>?</em><em> </em>

<em>Desculpe-me</em><em> </em><em>eu</em><em> </em><em>Nn</em><em> </em><em>consegui</em><em> </em><em>responder</em><em> </em><em>sua</em><em> </em><em>pergunta</em><em>.</em><em> </em>

<em>Mas</em><em> </em><em>mesmo</em><em> </em><em>assim</em><em>,</em><em> </em><em>agradeço</em><em> </em><em>pelos</em><em> </em><em>pontos</em><em> </em><em>estava</em><em> </em><em>precisando</em><em>.</em><em> </em>

<em>tchau</em><em>,</em><em> </em><em>tenha</em><em> </em><em>uma</em><em> </em><em>Ótima</em><em> </em><em>tarde</em><em>!</em><em> </em>

<em>Bons</em><em> </em><em>estudos</em><em> </em><em>nas</em><em> </em><em>suas</em><em> </em><em>atividades</em><em>!</em><em> </em><em>❤</em><em>♥</em>

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2.5% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac
Aleks04 [339]

Answer:

P(disease/positivetest) = 0.36116

Step-by-step explanation:

This is a conditional probability exercise.

Let's name the events :

I : ''A person is infected''

NI : ''A person is not infected''

PT : ''The test is positive''

NT : ''The test is negative''

The conditional probability equation is :

Given two events A and B :

P(A/B) = P(A ∩ B) / P(B)

P(B) >0

P(A/B) is the probability of the event A given that the event B happened

P(A ∩ B) is the probability of the event (A ∩ B)

(A ∩ B) is the event where A and B happened at the same time

In the exercise :

P(I)=0.025

P(NI)= 1-P(I)=1-0.025=0.975\\P(NI)=0.975

P(PT/I)=0.904\\P(PT/NI)=0.041

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

P(PT/I)=0.904

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

P(PT∩ I) = 0.0226

P(PT/NI)=0.041

P(PT/NI)=P(PT∩ NI)/P(NI)

0.041=P(PT∩ NI)/0.975

P(PT∩ NI) = 0.041 x 0.975

P(PT∩ NI) = 0.039975

P(PT) = P(PT∩ I)+P(PT∩ NI)

P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116

8 0
3 years ago
A curious patterns occurs in a group of people who all shake hands with one another. It turns out that you can predict the numbe
ycow [4]

Missing part of the question

Determine the number of handshakes, i, that will occur for each number of people, n, in a particular room. (people)

Answer:

S_n = \frac{n}{2}(n - 1)

Step-by-step explanation:

Given

For 5 people

\begin{array}{cc}{People} & {Handshakes} & {5} & {4} & {4} & {3} & {3} & {2} & {2} & {1} & {1} & {0} &{Total} & {10} \ \end{array}

Using the given instance of 5 people, the number of handshakes can be represented as:

(n - 1) + (n - 2) + (n - 3) + ........ + 3 + 2 + 1 + 0

The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.

S_n = \frac{n}{2}{(T_1 + T_n})

Where

T_1 = n - 1 --- The first term

T_n = 0 --- The last term

So:

S_n = \frac{n}{2}(n - 1 + 0)

S_n = \frac{n}{2}(n - 1)

7 0
2 years ago
In a school contest, each student draws a number from 1 to 5 out of a large basket. The outcomes are shown in the table below.
12345 [234]

Answer:

The answer is 88/407

Step-by-step explanation:

Their are 5 possible outcomes 1/83, 2/79, 3/88, 4/72, and 5/85. Trust me its 88/407

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3 years ago
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I’m saying (x+2) if you factor the denominators
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