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Elodia [21]
3 years ago
11

Ella makes this table to organize her notes on whether atoms gain or lose energy during the changes of state.

Physics
2 answers:
solong [7]3 years ago
7 0

Answer:

The answer is D.

fredd [130]3 years ago
5 0

Answer: D

Explanation: ummmmmmmmmmmmmmmmmmmmmmmmmmm = ̄ω ̄=

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If a light ray from a candle strikes a mirror at an angle of 40° with the normal, at what angle will the ray reflect?
pav-90 [236]

Answer:

the correct answer is b: 25

8 0
2 years ago
The initial velocity of a micro van is 15 m/s. It gains a velocity of 40 ms in 10 seconds. Calculate the average velocity and ac
PSYCHO15rus [73]

Answer:

{ \bf{average \: velocity =  \frac{15 + 40}{2}}} \\   = 27.5 \:  {ms}^{ - 1}  \\  { \bf{acceleration =  \frac{v - u}{t} }} \\  =  \frac{40 - 15}{10}  \\  = 2.5 \:  {ms}^{ - 2}  \\  \\ { \tt{second \: qn : }} \\ { \bf{final \: velocity =u + at }} \\ v = 0 + (5 \times 10) \\  = 50 \:  {ms}^{ - 1}

5 0
2 years ago
A 2 kg ball of putty moving to the right at 3 m/s has a perfectly inelastic, head-on collision with a 1 kg ball of putty moving
Aneli [31]

Answer:

V=1.33m/s   to the right

Explanation:

The balls collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V.

We need to use the conservation of momentum Law, the total momentum is the same before and after the collision.

In the axis X:

m_{1}*v_{o1}-m_{2}*v_{o2}=(m_{1}+m_{2})V     (1)

V=(m_{1}*v_{o1}-m_{2}*v_{o2})/(m_{1}+m_{2})=(2*3-1*2)/(2+1)=1.33m/s

5 0
2 years ago
During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where i
alukav5142 [94]

Answer:

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

d=vt+\frac{1}{2}at^2

Now by substituting values in, we get

d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2

d = 19.796m

7 0
2 years ago
It takes a truck 3.56 seconds to slow down from 112 km/h to 87.4 km/h. What is its average acceleration?
maxonik [38]

Answer:

option B

−1.92 m/s2

Explanation:

Given in the question,

time took by truck to slow down = 3.56 sec

initial speed of truck = 112 km/h

final speed of truck = 87.4 km/h

1 km/h = 0.277778 m/s

112 = 31.1 m/s

87.4 = 24.28 m/s

Formula use to calculate the acceleration

v - u = at

where v is final speed

           u is initial speed

           a is acceleration

           t is time

plug values in the equation

24.28 - 31.1 = a(3.56)

-6.8 = a(3.56)

a = -6.8 / 3.56

a = -1.9 m/s²

3 0
3 years ago
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