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Elodia [21]
3 years ago
11

Ella makes this table to organize her notes on whether atoms gain or lose energy during the changes of state.

Physics
2 answers:
solong [7]3 years ago
7 0

Answer:

The answer is D.

fredd [130]3 years ago
5 0

Answer: D

Explanation: ummmmmmmmmmmmmmmmmmmmmmmmmmm = ̄ω ̄=

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Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x.
Contact [7]
The center of mass is given with this formula:
x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}
Velocity is:
v=\frac{dv}{dt}
So, for the velocity of the center of mass we have:
\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\
v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\
In our case it is:
v_{xc}=\frac{m_1v_{x1}+m_2v_{x2}}{m_1+m_2}
 
5 0
3 years ago
All of the following elements produce magnetic fields except
KatRina [158]
The answer should be copper. hope this helps :D
6 0
3 years ago
Read 2 more answers
ILL GIVE BRAINLIEST!! URGENT PLEASE HELP
anygoal [31]
I believe the answer is the second one.
6 0
3 years ago
When a cube is inscribed in a sphere of radius r, the length Lof a side of the cube is . If a positive point charge Qis placed a
Nana76 [90]

Answer:

  Ф_cube /Ф_sphere = 3 /π

Explanation:

The electrical flow is

      Ф = E A

where E is the electric field and A is the surface area

Let's shut down the electric field with Gauss's law

       Фi = ∫ E .dA = q_{int} / ε₀

the Gaussian surface is a sphere so its area is

        A = 4 π r²

the charge inside is

        q_{int} = Q

we substitute

       E 4π r² = Q /ε₀

       E = 1 / 4πε₀   Q / r²

To calculate the flow on the two surfaces

* Sphere

       Ф = E A

        Ф = 1 / 4πε₀  Q / r² (4π r²)

        Ф_sphere = Q /ε₀

* Cube

Let's find the side value of the cube inscribed inside the sphere.

In this case the radius of the sphere is half the diagonal of the cube

          r = d / 2

We look for the diagonal with the Pythagorean theorem

         d² = L² + L² = 2 L²

         d = √2 L

         

we substitute

          r = √2 / 2 L

          r = L / √2

          L = √2  r

now we can calculate the area of ​​the cube that has 6 faces

          A = 6 L²

          A = 6 (√2  r)²

          A = 12 r²

the flow is

          Ф = E A

          Ф = 1 / 4πε₀  Q/r²  (12r²)

          Ф_cubo = 3 /πε₀  Q

the relationship of these two flows is

         Ф_cube /Ф_sphere = 3 /π

8 0
3 years ago
If u have a box with mass of 10kg and u push with a force of 200 N what is the acceleration of the box ?
AnnZ [28]

Answer:

20m/s²

Explanation:

force = mass*acceleration

acceleration = force ÷ mass

acceleration = 200N ÷ 10kg

acceleration = 20m/s²

5 0
3 years ago
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