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Afina-wow [57]
2 years ago
12

Protons Ha and Hb in the compound given are _________. homotopic enantiotopic diastereotopic mesotopic none of these

Chemistry
1 answer:
jek_recluse [69]2 years ago
8 0

Protons Ha and Hb in the compound given are enantiotopic.

<h3>What are enantiotopic protons?</h3>

Enantiotopic protons can be defined as those protons that can be replaced by another groups like deuterium.

<h3>What is a compound?</h3>

A compound is a substance which contains two or more elements chemically combined together.

So therefore, Protons Ha and Hb in the compound given are enantiotopic.

Learn more about enantiotopic protons:

brainly.com/question/24106290

#SPJ1

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Which statement explains how ATP and it's phosphate groups are relatedto energy that is used in plant processes
Zolol [24]

Hi my dear friend,

The statement that explain how ATP and its phosphate groups are related to energy used in plant process is that ADP gains a phosphate to create ATP, which stores energy for making sugars. These packets of energy in the form of ATP are then broken down to release energy and use that energy in synthesis of glucose.

~Thank you

8 0
3 years ago
The following physical constants are for water, H2O.
Delicious77 [7]

Answer:

Q\approx6.4~kJ

Explanation:

Quantity of heat required by 10 gram of ice initially warm it from -5°C to 0°C:

Q_1=m.C_s.\Delta T

here;

mass, m = 10 g

specific heat capacity of ice, C_s=2.09~J.g^{-1}.^{\circ}C^{-1}

change in temperature, \Delta T=(5-0)=5^{o}C

Q_1=10\times2.09\times 5

Q_1=104.5~J

Amount of heat required to melt the ice at 0°C:

Q_2=m.\Delta H_{fus}

where, \Delta H_{fus}=6020~J/mol

we know that no. of moles is = (wt. in gram) \div (molecular mass)

Q_2=\frac{10}{18} \times 6020

Q_2=3344.44~J

Now, the heat required to bring the water to 70°C from 0°C:

Q_3=m.C_L.\Delta T

specific heat of water, C_L=4.18~J/g/^oC

change in temperature, \Delta T=(70-0)=70^oC

Q_3=10\times 4.18\times 70

Q_3=2926~J

Therefore the total heat required to warm 10.0 grams of ice at -5.0°C to a temperature of 70.0°C:

Q=Q_1+Q_2+Q_3

Q=104.5+3344.44+2926

Q=6374.94~J

Q\approx6.4~kJ

8 0
3 years ago
Which is the most prevalent species in a 0.25 m aqueous solution of phosphoric acid h3po4 g?
kap26 [50]

Answer is: H₃PO₄.

A phosphoric acid is three protic acid, which means that in water release tree protons. Phosphoric acid ionizes in three steps in water.

<span> First step: H</span>₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).<span>
Second step: H</span>₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).<span>
Third step: HPO</span>₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).<span>
Species that are present: H</span>₃PO₄, H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺, but because the acid dissociation constants are low, very low percentage of acid dissociates.

8 0
3 years ago
A solution that contains the maximum amount of solute that is soluble at a given temperature is said to be —
solniwko [45]

Answer: Saturated

A solution that contains the maximum amount of solute that is soluble at a given temperature is said to be saturated.

Explanation:

A Saturated solution is one that contains as much (i.e maximum) solute as it can dissolve at that temperature in the presence of undissolved solute particles.

For instance: if a given volume of water can only dissolve a certain amount of salt in it at room temperature, then, more salt added will not dissolve.

Thus, making the solution saturated.

5 0
3 years ago
Convert a speed of 141 mi/h to units of feet per minute show work.
ozzi

Answer:

12408 feet per minute

Explanation:

Given: Speed is 141 mi/h

To find: speed in units of feet per minute

Solution:

Use the following units to convert the given speed into feet per minute.

1 mile = 5280 foot

1 h = 60 minutes

Therefore,

141 mi/h =\frac{141(5280)}{60} =12408 feet per minute.

3 0
3 years ago
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