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sdas [7]
3 years ago
11

What is the purpose of taller emissions stacks in industrial settings? a) They are intended to release particulates where there

is more wind to carry them away, but this also spreads pollution more widely. b) They allow chemical reactions to take place within the stack, thus creating less harmful particulates to be released from the stack. c) The taller emissions stack are a government requirements of the Clean Air Act Amendment, only serving the purpose of compliance to the law d) The particulates typically cannot be carried up in the airstream of a taller stack, so are naturally captured by gravity within the facility producing the pollution e) the taller emission stacks are meant to emit pollutants in a height where they are no longer pollutants any more
Chemistry
2 answers:
dusya [7]3 years ago
5 0
The correct option is A.
As part of the Clean Air Amendment, the government mandated industries to build emission stacks, through which pollutant can be released high into the air in order to prevent pollution of the local community. But this had resulted into interstate pollution, because at high altitudes, the wind carry the pollutants far away into other states or areas.

marissa [1.9K]3 years ago
5 0

the correct anwser is A

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Mole used in a chemistry sentence
katrin [286]
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7 0
3 years ago
What is the boiling point of a 1.5 m aqueous solution of fructose? the boiling point elevation constant of water is 0.515°c/m.
GREYUIT [131]
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.<span>
ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
 Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
5 0
3 years ago
How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat
inna [77]

Answer:

Explanation:

q= mc theta

where,

Q = heat gained

m = mass of the substance = 670g

c = heat capacity of water= 4.1 J/g°C    

theta =Change in temperature=( 66-25.7)

Now put all the given values in the above formula, we get the amount of heat needed.

q= mctheta

q=670*4.1*(66-25.7)

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=110704.1

8 0
3 years ago
What is an extensive property that can be calculated?
lord [1]
Volume can be calculated
4 0
2 years ago
Calculate the standard potential, e∘, for this reaction from its equilibrium constant at 298 k. x(s)+y4+(aq)↽−−⇀x4+(aq)+y(s)k=4.
laila [671]
First, we need to get the number of moles:

from the reaction equation when Y4+ takes 4 electrons and became Y, X loses 4 electrons and became X4+  

∴ the number of moles n = 4

we are going to use this formula:

㏑K = n *F *E/RT

when K is the equilibrium constant = 4.98 x 10^-5

and F is Faraday's constant = 96500

and the constant R = 8.314

and T is the temperature in Kelvin = 298 K

and n is number of moles of electrons = 4 

so, by substitution:

㏑4.98 x 10^-5 = 4*96500*E / 8.314*298

∴E = -0.064 V
6 0
3 years ago
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