Answer:
C2H5OH(l) + O2(g) → CO2(g) + ?H2O(l)
The coefficient should be 3
Explanation:
C2H5OH(l) + O2(g) → CO2(g) + ?H2O(l)
The chemical equation is a reaction between ethanol and oxygen . The reaction yield is carbon dioxide and water. Balancing the chemical equation requires one to make the number of atoms on the reactant side be equal to the number of atoms on the product side.
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)
The hydrogen atom on the left hand side of the equation is 6. Therefore, the number of atom of hydrogen should be 6 on the right hand side. The number of oxygen atom on the left hand side is 7. Therefore, the number of Oxygen atom on the right hand side should 7 . Oxygen atom in carbon dioxide(right hand side) is 4 atoms, therefore, it requires 3 atoms of oxygen to make the oxygen atoms 7.
Using 3 as the coefficient of water in the equation will make hydrogen 6 and oxygen 3 .Adding the 3 oxygen to the already 4 atoms of oxygen in carbon dioxide will make oxygen 7 atoms
Probably very negative or sightless negative
Benzene is more stable because it contains a ring and therefore an aromatic compound. On the other hand, 1,3,5-hexatriene, as a straight-chain alkene, is aliphatic. Aromatic compounds in general are more stable than their aliphatic counterparts because pi electrons are part of a conjugated system, meaning they are "shared" amongst all double-bonded atoms.
Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
Answer:
Some formulas for calculating mole are
Mole = Mass/ Molar mass
Mole = no of particles / avogadros constant
NB : no of particles can be no of atoms , no of ions , or no of molecules 2. Avogadros number or constant = 6.02 times 10 ^23
so we will be using the second formula
Mole = no of particles / avogadros constant
Mole = 5.03 x 10 ^23/6.02 x10^23
Mole = 8.355x10^45
hope it helps :)
Explanation: