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spin [16.1K]
3 years ago
12

After conducting SDS-PAGE, you will conduct a staining/destaining procedure, which allows for visual identification of the prote

ins in your gel. This procedure requires the following staining solution: Coomassie Blue staining solution: 0.1% Coomassie Blue dye (dry powder) in 50% methanol, 10% acetic acid.
Required:
How to make 1 L of this solution?
Chemistry
1 answer:
expeople1 [14]3 years ago
8 0

Answer:

Add 700mL of water.

Explanation:

The technique of separation known as the Sodium Dodecyl Sulfate Poly-Acrylamide Gel Electrophoresis in which its acronym is SDS- PAGE is a very important aspect of Chemistry and Biochemistry as the technique make use of molar mass when it work in seperating proteins.

From the question we have the following parameters or information:

Case 1=> 50% of methanol which is the same as saying 50mL in 100mL of water.

Case 2=> 0.1% Comasse Blue dye (dry powder) which is the same as saying 0.1g in 100mL of water.

Case 3=> 10% acetic acid is the same as saying 10mL in 100mL of water.

Adding the three together, we have ;

50mL in 100mL of water + 0.1g in 100mL of water + 10mL in 100mL of water.

The volume of water in the three = 100 mL + 100mL + 100mL = 300mL.

Therefore, there is need to add 700mL of water to make 1L.

That's 700mL of water + 300mL = 1000mL = 1L

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What is the maximum number of electrons in the following energy level? n = 3
11Alexandr11 [23.1K]
Answer is: 18 electrons.

<span>The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
The azimuthal quantum number (l) is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital, l = 0....n-1.</span>

<span>For n = 3, l = 0, 1, 2.</span>

<span>l = 0, s orbital with 2 electron.</span>

<span>l = 1, p orbitals with 6 electrons.</span>

<span>l = 2, d orbitals with 10 electrons.</span>

<span>2 + 6 + 10 = 18 electrons.</span>


8 0
4 years ago
Read 2 more answers
Compare 1 mole of H2, 1 mole of O2 and 1 mole of F2
likoan [24]

Explanation:

(a)  As per the mole concept, one mole of any atom contains 6.022 \times 10^{23} atoms or molecules, that is, Avogadro's number of atoms.

Therefore, 1 mole of H_{2} = 2 \times 6.022 \times 10^{23} molecules

                                           = 1.2044 \times 10^{23} molecules

   1 mole of O_{2} = 2 \times 6.022 \times 10^{23} molecules

                                    = 1.2044 \times 10^{23} molecules

   1 mole of F_{2} = 2 \times 6.022 \times 10^{23} molecules

                                    = 1.2044 \times 10^{23} molecules

Hence, there are equal number of molecules present in the given atoms.

(b)   Mass of each given atom will be calculated as follows.

                Mass = no. of moles × molar mass

As one molecule of H_{2} contains 2 atoms of hydrogen.

So, mass of 1 mole of H_{2} = 2 mol \times 1.008 g/mol

                                                     = 2.016 g

      mass of 1 mole of O_{2} = 2 mol \times 15.999 g/mol

                                                     = 31.996 g

      mass of 1 mole of F_{2} = 2 mol \times 18.998 g/mol

                                                     = 37.996 g

Thus, we can conclude that F_{2} has the greatest mass.

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4 years ago
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3 years ago
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Tanzania [10]

Explanation:

<em>According</em><em> </em><em>to</em><em> </em><em>your</em><em> </em><em>question</em><em>, </em>

<em>no</em><em>.</em><em> </em><em>a</em><em>.</em><em> </em><em>ans</em><em> </em><em>would</em><em> </em><em>be</em><em> </em><em>like</em><em>;</em><em> </em><em>chemical</em><em> </em><em>formula</em><em> </em><em>is</em><em> </em><em>defined</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>an</em><em> </em><em>expression</em><em> </em><em>which</em><em> </em><em>determines</em><em> </em><em>no</em><em>.</em><em> </em><em>and</em><em> </em><em>type</em><em> </em><em>of</em><em> </em><em>molecule</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>compound</em><em>. </em>

<em>b</em><em>.</em><em> </em><em>no</em><em>.</em><em> </em><em>ans</em><em>;</em><em> </em><em>it</em><em> </em><em>tells</em><em> </em><em>that</em><em> </em><em>what</em><em> </em><em>type</em><em> </em><em>of</em><em> </em><em>compound</em><em> </em><em>is</em><em> </em><em>formed</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>type</em><em> </em><em>and</em><em> </em><em>no</em><em>.</em><em> </em><em>of</em><em> </em><em>atoms</em><em> </em><em>present</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>atom</em><em>.</em>

<em>c</em><em>.</em><em> </em><em>no</em><em> </em><em> </em><em>ans</em><em>;</em><em> </em><em>the</em><em> </em><em>formulation</em><em> </em><em>of</em><em> </em><em>h2so4</em><em> </em><em>states</em><em> </em><em>that</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>acid</em><em> </em><em>named</em><em> </em><em>as</em><em> </em><em>hydrochloric</em><em> </em><em>acid</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>reacting</em><em> </em><em>of</em><em> </em><em>hydrogen</em><em> </em><em>(</em><em>2</em><em> </em><em>atoms</em><em> </em><em>)</em><em> </em><em>,</em><em>sulpher</em><em> </em><em>(</em><em>*</em><em>1</em><em>atom</em><em>)</em><em> </em><em>and</em><em> </em><em>oxygen</em><em>(</em><em>4</em><em>atoms</em><em>)</em><em>.</em>

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