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spin [16.1K]
3 years ago
12

After conducting SDS-PAGE, you will conduct a staining/destaining procedure, which allows for visual identification of the prote

ins in your gel. This procedure requires the following staining solution: Coomassie Blue staining solution: 0.1% Coomassie Blue dye (dry powder) in 50% methanol, 10% acetic acid.
Required:
How to make 1 L of this solution?
Chemistry
1 answer:
expeople1 [14]3 years ago
8 0

Answer:

Add 700mL of water.

Explanation:

The technique of separation known as the Sodium Dodecyl Sulfate Poly-Acrylamide Gel Electrophoresis in which its acronym is SDS- PAGE is a very important aspect of Chemistry and Biochemistry as the technique make use of molar mass when it work in seperating proteins.

From the question we have the following parameters or information:

Case 1=> 50% of methanol which is the same as saying 50mL in 100mL of water.

Case 2=> 0.1% Comasse Blue dye (dry powder) which is the same as saying 0.1g in 100mL of water.

Case 3=> 10% acetic acid is the same as saying 10mL in 100mL of water.

Adding the three together, we have ;

50mL in 100mL of water + 0.1g in 100mL of water + 10mL in 100mL of water.

The volume of water in the three = 100 mL + 100mL + 100mL = 300mL.

Therefore, there is need to add 700mL of water to make 1L.

That's 700mL of water + 300mL = 1000mL = 1L

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Ice is solid, however, water is liquid. Yet ice still floats which is less dense than water.

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4 0
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1. Addition of which of the following will increase the solubility of CaCO3 in water? Consider the equilibrium process:
kolbaska11 [484]

Answer: HCl

Explanation:

calcium carbonate dissolves in HCl acid producing CO 2 gas. It will not dissolve in pure water. The Ksp for calcium carbonate in water is 3.4 x 10-9 moldm-3 which is very low. What takes place here is actually a chemical reaction:

CaCO 3 (s) + 2HCl(aq) → CaCl 2 (aq) + H 2CO 3(aq)

This reaction accounts for the solubility of the Calcium carbonate in HCl and not in pure water.

6 0
3 years ago
What is the factor of 1024
Ugo [173]
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4 0
3 years ago
A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

7 0
3 years ago
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