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2 years ago

Elastic energy is stored when an object is stretched. Is this an example of potential or kinetic energy?

2 answers:

8 0

The correct answer is potential because kinetic energy means it’s moving. however it is stored and has the potential to be used

kakasveta [241]2 years ago

3 0

Answer:

<h2>potential </h2><h2 />

Explanation:

Each time energy is transferred into an object, two things happen.

It is either used to do work, or it is stored in the object.

If it is stored, the object is given potential energy that can be released to do work.

it is like in a coiled spring or a stretched elastic band. The energy is stored in the bonds between atoms. The bonds absorb energy as they are put under stress and release the energy as they relax (when the object returns to its original shape).

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Combustion vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a c

DochEvi [55]

Combustion equation of n-hexane:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles

LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1%

b)
1.1 volume percent required for LFL

1.1% x 1
= 0.0011 m³ of n-hexane required

6 0

3 years ago

Read 2 more answers

A student is investigating the effect of concentration on the colour of a solution of copper sulfate.She wished to make up 250cm

IrinaK [193]

Answer:

79.8g/dm³

Explanation:

As you can see, the solution in the problem contains 0.5 moles of copper sulfate per dm³. To solve this question we must convert these moles to grams using its molar mass (Molar mass CuSO4 = 159.609g/mol) as follows:

0.5mol CuSO4/dm³ * (159.609g/mol) =

3 0

2 years ago

A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.74 g of water at 52.2 oC in an insulated container. clead = 0.128

QveST [7]

Answer:

Explanation:

Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):

$DH_{lead}=-DH_{water}$

Now, by stating the heat capacity definition:

$m_{Pb}C_{Pb}*(T_{eq}-T_{lead}=-m_{H_2O}C_{H_2O}*(T_{eq}-T_{H_2O})\\$

Solving for the equilibrium temperature:

$T_{eq}=\frac{m_{Pb}C_{Pb}T_{Pb}+m_{H_2O}C_{H_2O}T_{H_2O}}{m_{Pb}C_{Pb}+m_{H_2O}C_{H_2O}} \\\\T_{eq}=\frac{2.04g*0.128J/(g^oC)*10.8^oC+7.74g*4.18J/(g^oC)*52.2^oC}{2.04g*0.128J/(g^oC)+7.74g*4.18J/(g^oC)} \\\\T_{eq}=51.87^oC$

Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.

Best regards.

5 0

2 years ago

What contribution did Niels Bohr make to atomic theory?

Bumek [7]

Answer:

Explanation

His greatest contribution is the atomic model

3 0

2 years ago

The vapor pressure of ethanol is 400. mmhg at 63.5°c. its molar heat of vaporization is 39.3 kj/mol. what is the vapor pressure

Vilka [71]

Answer: -

100 mm Hg

Explanation: -

P 1 =400 mm Hg

T 1 = 63.5 C + 273 = 336.5 K

T 2 = 34.9 C + 273 = 307.9 K

ΔHvap = 39.3 KJ/mol = 39.3 x 10³ J mol⁻¹

R = 8.314 J ⁻¹K mol⁻¹

Now using the Clausius Clapeyron equation

ln (P1 / P2) = ΔHvap / R x (1 / T2 - 1 / T1)

Plugging in the values

ln (400 mm/ P₂) = (39.3 x 10³ J mol⁻¹ / 8.314 J ⁻¹K mol⁻¹) x ( $\frac{1}{307.9 K}$ - $\frac{1}{336.5 K}$

= 1.38

P₂ = 100 mm Hg

6 0

3 years ago