What are the two cell division stages in the mitotic phase of the cell cycle?

g n the Ideal Gas Law lab, how is the temperature of the hydrogen gas determined? Select one: The pressure of the gas is determi

Charra [1.4K]

Answer:

The volume of the gas is determined, which will allow you to calculate the temperature.

Explanation:

According to Charles law; the volume of a given mass of an ideal gas is directly proportional to its temperature at constant pressure.

This implies that, when the volume of an ideal gas is measured at constant pressure, the temperature of the ideal gas can be calculated from it according to Charles law.

Hence in the Ideal Gas Law lab, the temperature of an ideal gas is measured by determining the volume of the ideal gas.

4 0

2 years ago

Chlorofluorocarbons (CFCs) are no longer used as refrigerants because they destroy the ozone layer. Trichlorofluoromethane (CCl₃

Daniel [21]

Answer:

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

Explanation:

Entropy :It is defined as amount of energy which is unable to do work or the measurement of randomness or disorderedness in a system.

$S=\frac{Q}{T(Kelvins)}$

Molar heat of molar vaporization of Trichlorofluoromethane = 24.8 kJ/mol

Temperature at which Trichlorofluoromethan boils , T= 296.95 K

The molar entropy of the evaporation of Trichlorofluoromethan :

$=\frac{24.8 kJ/mol}{296.95 K}=0.083516 kJ/mol K = 83.516 J/molK$

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

8 0

2 years ago

According to Le Chatelier’s principle, a change in pressure affects the chemical equilibrium of the reaction system under what c

charle [14.2K]

Some of the reactants or the products are in the gaseous phase.

7 0

3 years ago

Read 2 more answers

Which of the following is a safety precaution for handling radioactive material?

omeli [17]

C.) remove yourself from the radiation every 15 mins to prevent accumulation

7 0

2 years ago

Read 2 more answers

When methanol, CH 3 OH , is burned in the presence of oxygen gas, O 2 , a large amount of heat energy is released. For this reas

luda_lava [24]

<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams

<u>Explanation:</u>

We are given:

Amount of heat produced = 581 kJ

For the given chemical equation:

$CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l);\Delta H=-764kJ$

By Stoichiometry of the reaction:

When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole

So, when 581 kJ of heat will be produced, the amount of methanol reacted will be = $\frac{1}{764}\times 581=0.7605mol$

To calculate mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of methanol = 0.7605 moles

Molar mass of methanol = 32 g/mol

Putting values in above equation, we get:

$0.7605mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.7605mol\times 32g/mol)=24.34g$

Hence, the mass of methanol that must be burned is 24.34 grams

4 0

3 years ago