The answer is adequate nutrition, regular physical activity, and practical ways to reduce calories while retaining important nutrients.
Explanation:
Despite that adequate nutrition, regular physical activity, and practical ways to reduce calories while retaining important nutrients is one of the best strategy to reducing weight, most time it is very difficult for those that want to reduce or control their weight to discipline themselves enough to follow these routine. But one an individual that want to loose weight or live a healthy lifestyle is able to follow these procedures he/she will surely loose weight.
Answer:
Answer:
the amount of energy flowing is 1.008x10⁹J
Explanation:
To calculate how much heat flows, the expression is the following:
Where
K=thermal conductivity=0.81W/m°C
A=area=6.2*12=74.4m²
ΔT=30-8=22°C
L=thickness=8cm=0.08m
t=time=16.9h=60840s
Replacing:
Explanation:
Answer:
2.10L
Explanation:
Given data
V1= 2.5L
T1= 275K
P1= 2.1atm
P2= 2.7 atm
T2= 298K
V2= ???
Let us apply the gas equation
P1V1/T1= P2V2/T2
substitute into the expression we have
2.1*2.5/275= 2.7*V2/298
5.25/275= 2.7*V2/298
Cross multiply
275*2.7V2= 298*5.25
742.5V2= 1564.5
V2= 1564.5/742.5
V2= 2.10L
Hence the final volume is 2.10L
Answer:
Density of the object = 1.9399g/mL
Explanation:
Mass of object = 10.01g
Volume of water = 3.90mL
Volume of Object + Water = 9.06mL
Therefore, volume of Object = Volume of Object + Water - Volume of Water
= 9.06mL - 3.90mL
= 5.16mL
Density by definition is the mass per unit volume of a substance.
Density of the object = mass/volume
= 10.01/5.16
= 1.9399g/mL or 1.94kg/m3
1. 0.2 g/mL
The relationship between mass, density and volume of an object is
where
d is the density
m is the mass
V is the volume
For the object in this problem, we have
m = 10 g
V = 50 mL
Substituting into the equation,
2. 10 mL
In this exercise we know:
- The density of the object: d = 2 g/mL
- The mass of the object: m = 20 g
Therefore, we can re-arrange the previous equation to find the volume:
And substituting values into the equation, we find
