Answer:
a1 = 3.56 m/s²
Explanation:
We are given;
Mass of book on horizontal surface; m1 = 3 kg
Mass of hanging book; m2 = 4 kg
Diameter of pulley; D = 0.15 m
Radius of pulley; r = D/2 = 0.15/2 = 0.075 m
Change in displacement; Δx = Δy = 1 m
Time; t = 0.75
I've drawn a free body diagram to depict this question.
Since we want to find the tension of the cord on 3.00 kg book, it means we are looking for T1 as depicted in the FBD attached. T1 is calculated from taking moments about the x-axis to give;
ΣF_x = T1 = m1 × a1
a1 is acceleration and can be calculated from Newton's 2nd equation of motion.
s = ut + ½at²
our s is now Δx and a1 is a.
Thus;
Δx = ut + ½a1(t²)
u is initial velocity and equal to zero because the 3 kg book was at rest initially.
Thus, plugging in the relevant values;
1 = 0 + ½a1(0.75²)
Multiply through by 2;
2 = 0.75²a1
a1 = 2/0.75²
a1 = 3.56 m/s²
Answer:
10 kg
Explanation:
The question is most likely asking for the mass of the bicycle.
Momentum is the product of an object's mass and velocity. Mathematically:
p = m * v
Where p = momentum
m = mass
v = velocity
Hence, mass is:
m = p / v
From the question:
p = 25 kgm/s
v = 2.5 m/s
Mass is:
m = 25 / 2.5 = 10 kg
The mass of the bicycle is 10 kg.
In case the question requires the Kinetic energy of the bicycle, it can be gotten by using the formula
K. E = ½ * p * v
K. E. = ½ * 25 * 2.5 = 31.25 J
when wave propagate through the medium the medium particles have two type of possible motions
1) Transverse Waves : here medium particles will move perpendicular to wave propagation and they pull and push perpendicular to the length
2) Longitudinal wave : here medium particles will move to and fro along the length of the medium and the medium particles will push and pull together along the length of the string.
So here in two types of wave motion it will depends on the medium type as well as it will depend on the source how is wave produced.
So the given type of wave in which particles push together and pull apart the wave must be longitudinal wave.
Answer:
we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level
for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.
Explanation:
A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed of the rock at 2m on the way down compare with its speed at 2m on the way up?
It decreases in speed on its way down and increases in speed on its way down.
it decreases in speed on its way up because the the vertical motion is against the earths gravitational pull on an object to the earth's center
.It increases in speed on his way down because its under the influence of gravity
from newton's equation of motion we can check by
using V^2=u^2+2as
we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level
for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.
1,) C
2,) C
Hope this helps
