Question

all bearings are made by lebng spherical drops of molten metal fall inside a tall tower – called a shot tower – and solidify as they fall a height h. The bearings are released from rest. a)Draw the Problem. b)If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be? (LC) c)What is the bearing’s impact velocity? (LC)

Answer 1

Answer:

Part b)

h = 78.5 m

Part c)

v = 39.24 m/s

Explanation:

Part b)

If ball need t = 0 to t = 4 s then height of the tower is the total displacement of the ball in t = 4 s interval

here if ball start from rest

then its displacement is given as

$\Delta y = \frac{1}{2}gt^2$

$\Delta y = \frac{1}{2}(9.81)(4^2)$

$\Delta y = 78.5 m$

Part c)

Speed of the bearing at the end of the motion of the ball

$v_f = v_i + at$

$v_f = 0 + (9.81)(4)$

$v_f = 39.24 m/s$