Since both hv same mass and elsstic collision, so their velocity will exchange. Bob A will stop and bob B will move with speed of A just before the collision.
Speed will be = squreroot ( 2*g*L)
L is length of pendulum
Answer:
a) The magnitude of the car's total displacement (T) from the starting point is T = 82.67 Km
b) The angle (θ) from east of the car's total displacement measured from the starting direction is θ = 40.88 °
Explanation:
Attached you can see a diagram of the problem.
a) Find the magnitude of the vector T that goes from point A to point D (see the diagram).
The x and y components of this vector are
The magnitude of the vector is find using the pythagoras theorem:
, being a, b and c the 3 sides of the triagle that forms the vector:
Replacing the values
b) Find the angle θ that forms the vector T and the vector AB (see diagram).
To find this angle you can use the inverse tangent
θ
θ
θ=40.88°
Answer:
0.00019665625 N towards +x axis
0.0008091 N
towards +x axis
Explanation:
k = Coulomb constant =
= 3 nC
= -7 nC
= 5 nC
From Coulomb's law we have
The force is 0.000337125 N towards -x axis
The force is 0.00019665625 N towards +x axis
Net force on
The force is 0.000337125 N towards +x axis
The force is 0.000471975 N towards +x axis
Net force on
The force is 0.0008091 N towards +x axis