<u>Answer:</u> The pressure of carbon dioxide gas is 11 atm
<u>Explanation:</u>
To calculate the pressure of gas, we use the equation given by ideal gas equation:
PV = nRT
where,
P = pressure of the gas = ?
V = Volume of gas = 25 L
n = number of moles of gas = 10 mole
R = Gas constant = 
T = temperature of the gas = 325 K
Putting values in above equation, we get:
Hence, the pressure of carbon dioxide gas is 11 atm
Answer:
V₂ = 946.72 mL
Explanation:
Given data;
Initial pressure = 0.926 atm
Initial volume = 457 mL
Temperature = constant = 29.5°C
Final pressure = 0.447 atm
Final volume = ?
Solution:
The given problem will be solved through the Boyle's law,
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
by putting values,
P₁V₁ = P₂V₂
0.926 atm × 457 mL = 0.447 atm × V₂
V₂ = 423.18 atm. mL/ 0.447 atm
V₂ = 946.72 mL
Answer:
i would say B? Im sorry if im wrong
Explanation:
i think that because Catabolic reactions release energy, while anabolic reactions use up energy. Anabolism is the opposite of catabolism.
D.) the original components retain their individual properties
