The volume of the nitrous oxide gas is 1729.3 Liters
<h3>What is the number of moles of gas present in 3.40 kg of nitrous oxide?</h3>
The number of moles of gas present in 3.40 kg of nitrous oxide is determined from the formula below:
Numbers of moles = mass/molar mass
the mass of nitrous oxide = 3.40 kg or 3400 g
the molar mass of nitrous oxide = 44.013 g/mol
Moles of gas = 3400 / 44.013
Moles of gas = 77.25 moles
Using the ideal gas equation to determine the volume of the gas:
PV= nRT
V = nRT/P
where;
- V is the volume of gas
- n is the number of moles of gas
- R is molar Gas constant = 0.082 L.atm/mol/K
- T is the temperature of the gas
V = 77.25 * 0.082 * 273 / 1
The volume of the gas = 1729.3 Liters
Learn more about ideal gas equation at: brainly.com/question/20212888
#SPJ1
Answer:
light bulbs emit photons to produce light
Answer:
67.3 atm
Explanation:
We'll begin by converting 25 ℃ to Kelvin temperature. This can be obtained as follow:
T(K) = T(℃) + 273
T(℃) = 25 ℃
T(K) = 25 + 273
T(K) = 298 K
Finally, we shall determine the pressure. This can be obtained by using the ideal gas equation as illustrated below:
Gas constant (R) = 0.821 atm.L/Kmol
Volume (V) = 212 L
Number of mole (n) = 584 moles
Temperature (T) = 298 K
Pressure (P) =?
PV = nRT
P × 212 = 584 × 0.0821 × 298
P × 212 = 14288.0272
Divide both side by 212
P = 14288.0272 / 212
P = 67.3 atm
Thus, the pressure is 67.3 atm
Chemical properties
The process of changing into different substances is known as a chemical change and a substance exhibits its chemical properties during such a change.
