Answer:
<A=67⁰
<B=22⁰
<C=42⁰
<h2>Mark me BRAINLIEST </h2>
The answer to your question is: Yes, someone undoubtedly can.
Although you haven't asked to be told or shown how to solve it, I'm here
already, so I may as well stick around and go through it with you.
The sheet is telling you to find the solutions to two equations, AND THEN
DO SOMETHING WITH THE TWO SOLUTIONS. But you've cut off the
instructions in the pictures, so all we have are the two equations, and
you'll have to figure out what to do with their solutions.
<u>First equation:</u>
(2/5) x - 6 = -2
Add 6 to each side:
(2/5) x = 4
Multiply each side by 5:
2x = 20
Divide each side by 2 :
<u>x = 10</u>
<u>Second equation:</u>
-3y + 1/4 = 13/4
Subtract 1/4 from each side:
-3y = 12/4
Multiply each side by 4 :
-12 y = 12
Divide each side by -12 :
<u> y = -1</u>
Answer:
The two equations are
y = x - 3 and
3y = x + 9
Step-by-step explanation:
The options are not well stated. I'll answer the question without the options but however, my answer will be a reflection of one of the given options.
Given:
2 statements
Required
Write equivalent of both statements as equations
Let the large number be represented by x.
From the first statement (y, is equal to the difference of a larger number and 3)
Difference means minus (-); so, this statement is represented as follows to give us the first equation:
y = x - 3
From the second statement (The same number is one-third of the sum of the larger number and 9).
This is also represented as follows to give us the second equation
y = ⅓(x + 9)
Multiply both sides by 3
3 * y = 3 * ⅓(x + 9)
3y = x + 9
So, the two equations are
y = x - 3 and
3y = x + 9
Answer:
D. Miko found an incorrect quotient and checked her work using multiplication incorrectly
Step-by-step explanation:
We are given the equation
This can be rewritten as
Miko's work is incorrect as she did not multiply by the reciprocal of denominator's fraction. Instead she just multiplied by that fractions.
